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Mashutka [201]
3 years ago
9

Find the consecutive integers who's sum is -33

Mathematics
1 answer:
RUDIKE [14]3 years ago
6 0
-17,-16 because 
lets say the first integer is x
Then the second integer is x+1
Let's make an equation
x+(x+1)=-33
2x+1=-33
Subtract 1 from both sides
2x=-34
Divide both sides by 2
x=-17
The first number is -17
The second number is -16
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Secants L J and L M intersect and form an angle at point L. Solve for x.
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Answer:

x = 14  

Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}

Check:

\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}

It checks.

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Stratified sampling in statistics is applied to highlight contrasts within groups in a population, as objected to simple random sampling. Stratification is the part of something, primarily society, into various groups or layers.

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1. One way to approach this is to convert the magnitude and direction of each force to rectangular coordinates.

... first force = 90(cos(30°), sin(30°)) = (77.94, 45.00)

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Then their sum is

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The magnitude is found using the Pythagorean theorem:

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The resultant direction can be found using the definition of the tangent function.

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The (magnitude, direction) of the resultant force are (69.39, 63.55°).

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(Note that rounding introduced an error of 0.05° in the direction.)

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