Answer: A. A relation that is a function.
Step-by-step explanation:
A relation is said to be a function if each input value is associated with one unique output value.
Here, Number of miles run by car is directly proportional to the quantity of gasoline.
Independent variable - quantity of gasoline.
Dependent variable - Number of miles
On assuming the condition of car as good, the number of miles a car can run highly depends on the gallons of gasoline in the tank .
As quantity of gasoline increases number of miles driven would also increases.
i.e. Number of miles driven is a function with respect to quantity of gasoline.
Hence, the given line best describe as : A relation that is afunction.
Answer:
15
Step-by-step explanation:
Let index 1 refer to the first point, while index 2 refers to the second one.
The distance d:
d²=(x2-x1)²+(y2-y1)²=(-5-7)³+(3-(-6))²=
(-12)²+9²=144+81=225=15²
d=15
Answer:
47.33
Step-by-step explanation:
Hey there! I'm happy to help!
We have 8 bags of dog food and each costs $25.19
8(25.19)=201.52
And we have 11 leashes each costing $4.65.
11(4.65)=51.15
We add these totals up.
201.52+51.15=252.67
We subtract this from 300 to see how much is left.
300-252.67=47.33
Rhonda had $47.33 left after her purchases.
Have a wonderful day! :D
Step-by-step explanation:
= 2x - 9y + 4x + 11y
First of all combining like terms
So
= 2x + 4x - 9y + 11y
= 6x + 2y
Now putting values
= 6 (-2) + 2(4)
= - 12 + 8
= - 4
Answer:
At 7% $54,000
At 9% $156,000
Step-by-step explanation:
Let x be the amount invested at 7%, Then 2x + 48000 will be the amount invested at 9%
We know that:
7% = 0.07 & 9% = 0.09
So we can write the interest equation as follows:
0.07x + 0.09 (2x + 48000) = 17820
0.07x + 0.18x + 4320 = 17820
0.25x + 4320 = 17820
Subtracting 4320 from both sides of the equation we get:
0.25x = 17820 - 4320
0.25x = 13500
Dividing both sides of the equation by 0.25 we get:
x = 13500 / 0.25
x = $54,000 invested at 7%
&
2 x 54000 + 48000
= $156,000 invested at 9%
Hence the amount invested at 7% is $54,000.
& the amount invested at 9% is $156,000.