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polet [3.4K]
3 years ago
7

What are the cause of eye strain during computer usage?

Computers and Technology
1 answer:
Natasha2012 [34]3 years ago
5 0
It happens because your eyes follow the same path over and over. And it can get worse the longer you continue the movement. When you work at a computer, your eyes have to focus and refocus all the time. They move back and forth as you read. You may have to look down at papers and then back up to type. Your eyes react to changing images on the screen to create so your brain can process what you’re seeing. All these jobs require a lot of effort from your eye muscles. And to make things worse, unlike a book or piece of paper, the screen adds contrast, flicker, and glare.

You’re more likely to have problems if you already have eye trouble, if you need glasses but don't have them, or if you wear the wrong prescription for computer use.

Computer work gets harder as you age and the lenses in your eyes becomes less flexible. Somewhere around age 40, your ability to focus on near and far objects will start to go away. Your eye doctor will call this condition presbyopia.

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Read 2 more answers
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Answer:

Explanation:

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Assume that a function named swapdoubles has been defined and is available for use in this exercise: that function receives two
Nata [24]

Answer:

C++ Code:

void sort3(double &a, double &b, double &c)

{

   if(a > b)

       swapdoubles(a,b);

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       swapdoubles(b,c);

   if (a > b)

       swapdoubles(a,b);

}

Explanation:

To change the values of a,b,c within the function, we pass the values by reference. Let us assume that number a = 3.14, b = 2.71, c = 3.04. Since a > b, values of a and b will be swapped.Now a = 2.71 and b = 3.14. Similariy, since b > c, they will be swapped. This way, we move the largest number to its correct position in the first two steps. If there are only three numbers, and the largest number is in its correct position, then for the two remaining numbers, we will only need atmost one swap to exchange their positions. hence, we perform a comparison of a > b once again to see if the b is smaller than a. if its not, then all a,b,c are in sorted order.

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