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tangare [24]
3 years ago
14

The diameter of a circle has endpoints whosever coordinates are R(-2,2) and S(4,2). find the center of the circle

Mathematics
1 answer:
lisov135 [29]3 years ago
3 0
Hello!

As you can see this line is horizontal. It is 6 units long. Therefore the center is three units in. Therefore the center of this circle is at (1,2).

I hope this helps!
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Given the functions, f(x) = 5x2 - 3x + 1 and g(x) = 2x2 + x - 2, perform the indicated operation. When applicable, state the dom
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You plug in 1,2,3 and so on in the X and you graph , i think
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3 years ago
What is the solution to the system of equations?
Dovator [93]

Answer:

<h2>(-10, 2, 6)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}x+3y+2z=8&(1)\\3x+y+3z=-10&(2)\\-2x-2y-z=10&(3)\end{array}\right\qquad\text{subtract both sides of the equations (1) from (2)}\\\\\underline{-\left\{\begin{array}{ccc}3x+y+3z=-10\\x+3y+2z=8\end{array}\right }\\.\qquad2x-2y+z=-18\qquad(4)\qquad\text{add both sides of the equations (3) and (4)}\\\\\underline{+\left\{\begin{array}{ccc}-2x-2y-z=10\\2x-2y+z=-18\end{array}\right}\\.\qquad-4y=-8\qquad\text{divide both sides by (-4)}\\.\qquad\qquad y=2\qquad\text{put the value of y to (1) and (3)}

\left\{\begin{array}{ccc}x+3(2)+2z=8\\-2x-2(2)-z=10\end{array}\right\\\left\{\begin{array}{ccc}x+6+2z=8&\text{subtract 6 from both sides}\\-2x-4-z=10&\text{add 4 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+2z=2&\text{multiply both sides by 2}\\-2x-z=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+4z=4\\-2x-z=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad3z=18\qquad\text{divide both sides by 3}\\.\qquad\qquad z=6\qquad\text{put the value of z to the first equation}

x+2(6)=2\\x+12=2\qquad\text{subtract 10 from both sides}\\x=-10

4 0
3 years ago
16. The original price of a tie is $12.50. The new price of the tie is now
jarptica [38.1K]
The tie was marked down by 40%
4 0
2 years ago
-10 = y/11 - 13<br><br> solve for y
Flauer [41]

Answer:

10=y/11-13

We move all terms to the left:

-10-(y/11-13)=0

-y/11+13-10=0

We multiply all the terms by the denominator

-y+13*11-10*11=0

We add all the numbers together, and all the variables

-1y+33=0

We move all terms containing y to the left, all other terms to the right

-y=-33

y=-33/-1

y=+33

6 0
2 years ago
Read 2 more answers
Please help!! ASAP!!!!
Softa [21]
Tan(theta)= pi

Now, in order for you to find the angle (theta), you would inverse tan both the left and the right to find the value. The inverse of tan is tan^-1.

tan(theta)=pi ---> theta = tan^-1(pi)

Then, you would plug tan^-1(pi) into a calculator, giving you the value 

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