Answer:
2/10
Step-by-step explanation:
Probability of getting head on i'th coin = i/10
Probability Pr of getting head on 2nd coin (Event A) = 2 / 10
Probability Pr of getting head on 1st coin (Event B) = 1/10
Probability A given B = Pr (A/B) = Pr (A∩B) / Pr B ;
where A∩B = Pr (A & B) = Pr A X Pr B
Putting in above formula :
Pr (A/B) = <u>[(</u>1/10)x(2/10<u>)]</u> / 1/10
= 2/10
First you must find a common denominator. In this case 10 will work. You then multiply the top number by whatever you multiplied the bottom number by. This is shown below:
4/5- 3/10 = 8/10- 3/10
You can now solve this to get 5/10. This answer can then be reduced to 1/2.
Answer:
C) 15
Step-by-step explanation:
Here we have to use the combination to find the number of possible combinations.
Total number of classmates (n) = 6
We are selecting 2 individuals. So r = 2.
The combination formula nCr = 
Plug in n = 6 and r =2, in the above formula, we get
= 
= 
Simplifying the above factorial, we get
= 15
So the answer is C) 15
Yea because every input has only one output
17% are lions, 3/10 = 30% are zebras, therefore the remaining 100 - 47 = 53% of animals are tigers.
