Hmm, one way we can do this is by assigning numbers to each
A=4 and B=3
A>B because 4>3
so
A. 2(A+B)=2(4+3)=2(7)=14
B. A+B^2=4+3^2=4+9=13
C. A^2+B^2=4^2+3^2=16+9=25
D. A^2-B^2=4^2-3^2=16-9=7
the largest is 25 so C
The answer for the question is 428
Answer:
h(x) = -16x² + 192x + 208
784ft
6 sec
13 sec
Step-by-step explanation:
a)
h(x) = -16x² +vx + h
here v represent velocity
represent initial height of launch
h(x) = -16x² + 192x + 208
b)
h(x) = -16x² + 192x + 208
here a = -16
b = 192
c = 208
x = -b/2a
= -192/2(-16)
= 6
plug this value in the equation
h(x) = -16(6)² + 192(6) + 208
= 784ft
e)
Plug h(x)=0 in the equation
0 = -16x² + 192x + 208
divide equation by -16
x² - 12x - 13 = 0
Factors
1x * -13x = -13
1x - 13x = -12
Factorised form
x² - 12x - 13 = 0
x² + x - 13x - 13 = 0
x(x+1) -13(x+1) = 0
(x+1)(x-13) = 0
x = -1
x = 13
Since time can not be negative so we will reject x = -1
A. 0.15 Because its making me type twenty characters.