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IrinaVladis [17]
3 years ago
7

Multiply (m-6)=3m + 14

Mathematics
2 answers:
V125BC [204]3 years ago
7 0

Answer:Solve

1

Eliminate redundant parentheses

(

−

6

)

=

3

+

1

4

−

6

=

3

+

1

4

2

Add

6

6

6

to both sides of the equation

−

6

=

3

+

1

4

−

6

+

6

=

3

+

1

4

+

6

3

Simplify

Add the numbers

Add the numbers

=

3

+

2

0

4

Subtract

3

3m

3m

from both sides of the equation

=

3

+

2

0

−

3

=

3

+

2

0

−

3

5

Simplify

Combine like terms

Combine like terms

−

2

=

2

0

Step-by-step explanation:

Levart [38]3 years ago
4 0

Answer:

Step-by-step explanation:

m=10

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Step-by-step explanation:


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Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

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I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

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Step-by-step explanation:

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B. 4

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Step-by-step explanation:

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