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IrinaVladis [17]
3 years ago
7

Multiply (m-6)=3m + 14

Mathematics
2 answers:
V125BC [204]3 years ago
7 0

Answer:Solve

1

Eliminate redundant parentheses

(

−

6

)

=

3

+

1

4

−

6

=

3

+

1

4

2

Add

6

6

6

to both sides of the equation

−

6

=

3

+

1

4

−

6

+

6

=

3

+

1

4

+

6

3

Simplify

Add the numbers

Add the numbers

=

3

+

2

0

4

Subtract

3

3m

3m

from both sides of the equation

=

3

+

2

0

−

3

=

3

+

2

0

−

3

5

Simplify

Combine like terms

Combine like terms

−

2

=

2

0

Step-by-step explanation:

Levart [38]3 years ago
4 0

Answer:

Step-by-step explanation:

m=10

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Hmm, one way we can do this is by assigning numbers to each

A=4 and B=3
A>B because 4>3

so

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An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach
Alexeev081 [22]

Answer:

h(x) = -16x² + 192x + 208

784ft

6 sec

13 sec

Step-by-step explanation:

a)

h(x) = -16x² +vx + h_{o}

here v represent velocity

         h_{o} represent initial height of launch

       

h(x) = -16x² + 192x + 208

b)

h(x) = -16x² + 192x + 208

here a = -16

        b = 192

        c = 208

x = -b/2a

  = -192/2(-16)

  = 6

plug this value in the equation

h(x) = -16(6)² + 192(6) + 208

      = 784ft

e)

Plug h(x)=0 in the equation

0 = -16x² + 192x + 208

divide equation by -16

x² - 12x - 13 = 0

Factors

1x * -13x = -13

1x - 13x = -12

Factorised form

x² - 12x - 13 = 0

x² + x - 13x - 13 = 0

x(x+1) -13(x+1) = 0

(x+1)(x-13) = 0

x = -1

x = 13

Since time can not be negative so we will reject x = -1  

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