We can solve this problem using discriminant.
x^2-4x-12's discriminant is
(-4)^2-4*-12=16+48 which is clearly larger than 0
This means that it crosses over the axes 2 times.
In case you don't know what discriminant is, its in equation ax^2+bx+c
the discriminant is b^2-4ac.
If its positive it has 2 crosses with x axis, if negative then 0 crosses, if 0 then 1 cross.
Hope this helped at least a little bit :D
Answer:
Step-by-step explanation:
Good evening ,
P(A|B) = P(A∩B)/P(B)
P(B|A) = P(A∩B)/P(A)
:)
Answer:

Step-by-step explanation:

Lets expand all the composite numbers into prime numbers.

Lets cancel
from numerator and denominator.

Using laws of exponents , lets solve this.


![=> 3^{-3} \times 5^{[1 - (-2)]}](https://tex.z-dn.net/?f=%3D%3E%203%5E%7B-3%7D%20%5Ctimes%205%5E%7B%5B1%20-%20%28-2%29%5D%7D)


Answer:325,000
Step-by-step explanation:
4 gets rounded up to 5 because of the 6 next to it.
-5 = 3/4x - 2
-5 + 2 = 3/4x
-3 = 3/4x
-3 / (3/4) = x
-3 * 4/3 = x
-12/3 = x
-4 = x <==