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Slav-nsk [51]
3 years ago
8

HELPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
matrenka [14]3 years ago
3 0
If 3 = m^x, then we know 9 = (m^x)^2 because 9 is 3 squared.

(m^x)^2 can be simplified to m^{2x}

So now we know 9m^2 = m^{2x}·m^2

Since m^{2x} and m^2 have the same base, we can express it as a single term by adding the exponents together.

So the answer is C) m^{2x+2}
You might be interested in
Given the side lengths, determine whether thr triangle is acute, right, ovtuse, or not a triangle:
DaniilM [7]

Answer:

1) If sum of the two smaller sides of a triangle is greater than the third longer side, then its a triangle.

<h3>In our case, 20 + 23 > 41. Hence its a triangle .</h3>

Use the side lengths to classify the triangle as acute, right, or obtuse. Compare the square of the length of the longest side with the sum of the squares of the lengths of the two shorter sides

2) Square root of sum of the squares of the two smaller sides is equal to the third longer side, then its a right triangle.

In our case,

√20^2+23^2≈30.4795<41.

<h3>Hence not a right triangle.</h3>

Since the sum of the squares of the two shorter sides is < the square of the longer side, its an obtuse angle triange

Step-by-step explanation:

Hope it is helpful....

6 0
3 years ago
Determine whether the formula describes y as a function of x. y = -3x2 - 7x - 6 Explain your reasoning
AleksAgata [21]
Yes because when you have y = -3x²-7x -6 it is just the same as f(x) = -3x² -7x - 6
6 0
3 years ago
If f(x)=1/x and g(x)=2x+1, find f(g(1)) and g(f(2)).
mel-nik [20]

Answer:

f(g(1))=1/3

g(f(2))=1

Step-by-step explanation:

For f(g(1)) plug the 1 in the x in thefunction of g, and plug g in the x in the function f.

Do the same thing for g(f(2)) using the number 2

6 0
3 years ago
What are the zeros of the quadratic function?<br> y = x^2 - 2x - 15
Pie

Answer:

x=\frac{1+\sqrt{31}}{2},\:x=\frac{1-\sqrt{31}}{2}

Step-by-step explanation:

-> 0=2x^2-2x-15

-zeros means the solution aka x intercept, meaning y=0

x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:2\left(-15\right)}}{2\cdot \:2}

=> according to quadratic formula

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

where ax^2+bx+c=0

=> x_{1,\:2}=\frac{-\left(-2\right)\pm \:2\sqrt{31}}{2\cdot \:2}

simplify

x_1=\frac{-\left(-2\right)+2\sqrt{31}}{2\cdot \:2},\:x_2=\frac{-\left(-2\right)-2\sqrt{31}}{2\cdot \:2}

x=\frac{1+\sqrt{31}}{2},\:x=\frac{1-\sqrt{31}}{2}

Cannot simplify farther

3 0
2 years ago
What are the determinants for solving this linear system? 5x + 3y = 17 −8x − 3y = 9 |A| = |Ax| = |Ay| =
valentina_108 [34]

For this case we have the following system of equations:

5x + 3y = 17\\-8x - 3y = 9

We can Rewrite the system of equations of the form:

Ax = b

Where,

A: coefficient matrix

x: incognita vector

b: vector solution

We have then:

A=\left[\begin{array}{ccc}5&3\\-8&-3\end{array}\right]

x=\left[\begin{array}{ccc}x\\y\end{array}\right]

b=\left[\begin{array}{ccc}17\\9\end{array}\right]

Then, the determinant of matrix A is given by:

|A|=(5)(-3)-(3)(-8)\\

|A|=-15+24

|A|=9

Answer:

The determinants for solving this linear system are:

|A|=9

7 0
3 years ago
Read 2 more answers
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