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3 years ago

A group of 5 men are meeting for lunch.

Mathematics

1 answer:

Sladkaya [172]3 years ago

6 0

Tile:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

There were total 5 men wearing coats.

5 coats can be returned to 5 men in 5! = 120 ways.

The coats can be returned to the accurate persons only in 1 way.

Hence, the probability that each man gets the correct coat is $\frac{1}{120}$ .

(b)

At the time of returning the first coat, the hostess will have 5 choices and for the second she will have 4 choices.

Hence, in $5\times4 = 20$ ways the hostess can return the 2 coats.

There is only 1 possible case that each of the coats will return to the correct owner.

Hence, the required probability is $\frac{1}{20}$ .

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May anyone help me out with this question please

tangare [24]

4/52 = 1/13 <== here ya go

6 0

3 years ago

Which estimate is closest to the actual value of (2.99548) ⋅ (1.8342)? CHOOSE ALL THAT APPLY!

docker41 [41]

I think B. Would be the correct one

5 0

2 years ago

6=2(y+2) i need help

Snowcat [4.5K]

Answer:

y=1

Step-by-step explanation:

6=2(y+2)

6=2y+4

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3 0

2 years ago

Read 2 more answers

charlie had a circular patio with a radius of 6 feet. the radius is 12 bricks in length. how many bricks would be in the diamete

alex41 [277]

Answer:

24 Bricks.

Step-by-step explanation:

We know the radius is 6 feet and that the diameter is twice that.

We also know the radius is 12 'bricks' in length.

If we divide both numbers by 12, we get that 1 'brick' is half a foot.

Since that's the radius and we want the diameter, we multiply the radius by 2 to get the diameter.

This results in 12 feet, or 24 'bricks'.

7 0

3 years ago

It costs more to produce defective items - since they must be scrapped or reworked - than it does to produce non-defective items

ale4655 [162]

Answer: a) 1082, b) wider.

Step-by-step explanation:

Since we have given that

Margin of error = 0.1 millimeter = E

Standard deviation = 2 mm = σ

Critical value would be

$z_{\frac{\alpha}{2}}=z_{0.05}=1.645$

a) Sample size would be

$n=(\dfrac{z_{\frac{\alpha }{2}}\times \sigma}{E})^2\\\\n=(\dfrac{1.645\times 2}{1})^2\\\\n=1082.41\\\\n=1082$

b) Sample size, n = 100

So, the margin of error would be

$E=z_{\frac{\alpha }{2}}\times \dfrac{\sigma}{\sqrt{n}}\\\\E=1.645\times \dfrac{2}{\sqrt{100}}\\\\E=1.645\times \dfrac{2}{10}\\\\E=0.329$

Since the margin of error in b part is more than a part, as we know that the higher the margin of error, the wider the confidence interval.

So, it would have wider confidence interval.

Hence, a) 1082, b) wider.

4 0

3 years ago