A group of 5 men are meeting for lunch.

Mathematics

1 answer:

Sladkaya [172]2 years ago

6 0

Tile:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

There were total 5 men wearing coats.

5 coats can be returned to 5 men in 5! = 120 ways.

The coats can be returned to the accurate persons only in 1 way.

Hence, the probability that each man gets the correct coat is $\frac{1}{120}$ .

(b)

At the time of returning the first coat, the hostess will have 5 choices and for the second she will have 4 choices.

Hence, in $5\times4 = 20$ ways the hostess can return the 2 coats.

There is only 1 possible case that each of the coats will return to the correct owner.

Hence, the required probability is $\frac{1}{20}$ .

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Step by step please and thank you.

cupoosta [38]

Answer:

the probability is 2/9

Step-by-step explanation:

Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).

p(dime first) = 4/10 = 2/5

Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.

The joint probability of these two events occurring sequentially is the product of their probabilities:

p(dime then nickel) = (2/5)×(5/9) = 2/9

_____

<em>Alternate solution</em>

You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.

p(dime/nickel) = 20/90 = 2/9

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2 years ago

Determine the value of y when x=15 if y=6 when x =30

Vladimir79 [104]

6+9=15
y+9=x
x=30
y+9=30
y=21

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2 years ago

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Rina8888 [55]

Answer:

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