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lions [1.4K]
3 years ago
13

Helppp ill mark u as brainlist ​

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0

Answer:

I think to my beliefs is gold God and glory I think and I like your hand writing by the way

You might be interested in
PLEASE SHOW YOUR WORK!!! (solve system of equations by adding, subtracting, or multiplying.)
Aliun [14]
Hey friend, hope I can assist you!
I will solve by elimination <3.
Multiply 3x - 7y = 2 by 2: 6x - 14y = 4
6x - 14y = 4
6x - 9y = 9
5y = 5
Now we have
6x - 14y = 4
5y = 5
Now we want to solve 5y = 5 for y
So simply divide both sides by 5.
5y/5 = 5/5
This gives us one or in other words, y = 1.
Now we want to plug y = 1 into  6x - 14y = 4
So 6x - 14 * 1 = 4
This gives us
6x - 14 = 4
Now add 14 to both sides.
6x - 14 + 14 = 4 + 14
6x = 18
Now divide both sides by 6
6x/6 = 18/6
This gives us 3 so x = 3
Therefore our solutions to this system of equations would be y = 1 and x = 3

5 0
3 years ago
Which expression is equivalent to 4x2 - 4x – 3 in factored form?
erastovalidia [21]

Answer:

(2x-3)(2x+1)

Step-by-step explanation:

4x^2 - 4x - 3

we need two numbers that give 12 when multiplied and 4 when subtracted

the numbers are 6 and 2 because 6*2=12 and 6-4=4.

4x^2 - (6-2)x -3

4x^2 -6x +2x -3

take common

2x(2x -3)+1(2x-3)

take (2x-3) as common

(2x-3)(2x*1 + 1*1)

(2x-3)(2x+1)

3 0
2 years ago
Reduce the Fractions 15/9to its Lowest Terms
KatRina [158]

\large\bf{\red{  \implies}} \tt \:   \cancel\frac{15}{9}   \\

\large\bf{\red{  \implies}} \tt \:   \frac{5}{3}  \\

Decimal Form - 1.6667

6 0
2 years ago
What is the quotient of StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction? Star
Komok [63]

The quotient of the number given number  7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline is 7.

<h3>What is the quotient?</h3>

Quotient is the resultant number which is obtain by dividing a number with another. Let a number a is divided by number b. Then the quotient of these two number will be,

q=\dfrac{a}{b}

Here, (<em>a, b</em>) are the real numbers.

The number StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction, given can be written as,

\dfrac{7^{-1}}{7^{-2}}

Let the quotient of this division is n. Therefore,

n=\dfrac{7^{-1}}{7^{-2}}

A number in numerator of a fraction with negative exponent can be written in the denominator with the same but positive exponent and vise versa. Therefore,

n=\dfrac{7^{2}}{7^{1}}\\n=7

Hence, the quotient of the number given number  7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline is 7.

Learn more about the quotient here;

brainly.com/question/673545

7 0
2 years ago
N is a rational number.m is an irrational number.n2 cannot be an irrational number? why or why not
Korolek [52]

If n is rational, it means that

n\in\mathbb{Q}\Rightarrow n=\frac{p}{q},\quad p\in\mathbb{Z},\quad q\in\mathbb{Z}^*

Therefore when we do n² we can write it as

n^2=\frac{p^2}{q^2},\quad p\in\mathbb{Z},\quad q\in\mathbb{Z}^*

Remember that the product of two integer numbers is also an integer, therefore we can guarantee that

p^2\in\mathbb{Z}\text{ and }q^2\in\mathbb{Z}^*

Then we can confirm that n² is the quotient of two integers and the denominator is not zero, therefore, n² is always rational, it cannot be an irrational number

8 0
1 year ago
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