Answer:
<em>The point lies barely outside of the circle</em>
Step-by-step explanation:
<u>Equation of a Circle</u>
Given its center (h,k) and radius r, the equation of a circle is given by
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
The circle given in the question is centered at (7,8) and has a radius of 6, thus its equation is
![(x-7)^2+(y-8)^2=6^2](https://tex.z-dn.net/?f=%28x-7%29%5E2%2B%28y-8%29%5E2%3D6%5E2)
![(x-7)^2+(y-8)^2=36](https://tex.z-dn.net/?f=%28x-7%29%5E2%2B%28y-8%29%5E2%3D36)
To find out if a point (a,b) is outside or inside the circle area, the following conditions apply.
if
then the point lies outside of the circle area
if
then the point lies inside of the circle area
Let's use the point as given (6,2)
![(6-7)^2+(2-8)^2=1+36=37](https://tex.z-dn.net/?f=%286-7%29%5E2%2B%282-8%29%5E2%3D1%2B36%3D37)
Thus the point lies barely outside of the circle
Answer:
25m + 3
Step-by-step explanation:
Break the bracket, you will get:
- -25m - (-3)
= + 25m + 3
= 25m + 3
Hope this helped :3
O get the Least Common Multiple (LCM) of 15 and 8 we need to factor each value first and then we choose all the factors which appear in any column and multiply them:
<span><span>15: 35</span><span>8: 222 </span><span>LCM: 22235</span></span>
<span>The Least Common Multiple (LCM) is: 2 x 2 x 2 x 3 x 5 = 120</span>
Answer:
A jar 6red ball 3green ball 5 white ball 7yellow ball
Answer:
A and D
Step-by-step explanation: