The temperature fell by 13degrees Fahrenheit today. Write a signed number to represent this temperature change.

The area of a tabletop is 48 square feet. the length is 3 times the width.if the dimensions are whole numbers, what is the width

posledela

(4 feet wide), 12 feet in length. 4*3=12 4*12=48

7 0

3 years ago

My Space Mathematician Teacher needs this answer,

GaryK [48]

219864070186 - 277409297400 = -57545227214 x 780498 = -4.4913935e+16 - 1274806769367926946610431 = -1.2748068e+24 x 3.6614422e+21 = -4.6676314e+45 - 437913 = -4.6676314e+45 - 88878 = -4.6676314e+45

Ф = 500 , 5,000

5,000 / ∞ x ∞ x ∞ = 5,000^+++∞/ 68307147 = 0.00007319878^+++∞ - 917 - 974 - 9 - 19344381 = -19346280.9999^+++∞

-4.6676314e+45 -19346280.9999^+++∞ = -4.6676314e+45^+++∞

I believe that will be your answer.

I tried my best.

4 0

3 years ago

A trapezoid is shown. The lengths of the bases are 4 and 8. The height of the altitude is 4. What is the area of the trapezoid?

katrin [286]

It would be 24 units^2 because the middle is 16 and the two triangles are 4 each

3 0

3 years ago

Read 2 more answers

You have measured the systolic blood pressure of a random sample of 25 employees of a company located near you. A 95% confidence

Alla [95]

Answer:

$122 \leq \mu \leq 138$

The 95% confidence interval would be given by (122;138)

And the correct interpretation for this case is:

c. If the procedure were repeated many times, 95% of the resulting confidence intervals would contain the population mean systolic blood pressure.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % where by a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=25-1=24$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,24)".And we see that $t_{\alpha/2}=2.06$