What is the common ratio of the geometric sequence whose first term

1 answer:

3 0

$a_1=27;\ a_4=64\\\\a_4:a_1=d^3\\\\subtitue\\\\d^3=64:27\\\\d^3=\dfrac{64}{27}\\\\d=\sqrt[3]{\dfrac{64}{27}}\\\\d=\dfrac{\sqrt[3]{64}}{\sqrt[3]{27}}\\\\d=\dfrac{4}{3}\\\\Answer:\boxed{(3)\ \frac{4}{3}}$

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