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Alecsey [184]
4 years ago
9

What is the common ratio of the geometric sequence whose first term

Mathematics
1 answer:
Anuta_ua [19.1K]4 years ago
3 0
a_1=27;\ a_4=64\\\\a_4:a_1=d^3\\\\subtitue\\\\d^3=64:27\\\\d^3=\dfrac{64}{27}\\\\d=\sqrt[3]{\dfrac{64}{27}}\\\\d=\dfrac{\sqrt[3]{64}}{\sqrt[3]{27}}\\\\d=\dfrac{4}{3}\\\\Answer:\boxed{(3)\ \frac{4}{3}}
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</span>d1 = \sqrt{(-20-(-12))^{2} +(-9-(-16))^{2}} =\sqrt{(-20+12)^{2} +(-9+16)^{2}} \\ =\sqrt{(-8)^{2} +(7)^{2}}= \sqrt{64+49} = \sqrt{113}= 10.63

Distance 2: Blythe (–20, –9) to Los Angeles (–33, –4):
d2 = \sqrt{(-33-(-20))^{2} +(-4-(-9))^{2}} =\sqrt{(-33+20)^{2} +(-4+9)^{2}} \\ =\sqrt{(-13)^{2} +(5)^{2}}= \sqrt{169+25} = \sqrt{194}= 13.93

Distance 3: Los Angeles (–33, –4) to <span>San Francisco (–36, 5)
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D = d1 + d2 + d3 = 10.63 + 13.93 + 9.49 = 34.05</span>
3 0
3 years ago
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