Let U = {1, 2, 3, 4, 5, 6, 7}, A= {1, 3, 4, 6}, and B= {3, 5, 6}. Find the set A’ U B’
Art [367]
Answer:
Step-by-step explanation:
A'={2,5,7}
B'={1,2,4,7}
A'UB'={1,2,4,5,7}
Answer:
6 matches
Step-by-step explanation:
Let’s call the teams A B C D
A will play B C D = 3 matches
B will play only C and D as it already played A, making 2 matches
C will play D, making 1 match
D has already played all
Total number of matches is thus 3 + 2 + 1 = 6 matches
The order is: 9.036, 9.535, and 9.982.
Answer:
a) 0.778
b) 0.9222
c) 0.6826
d) 0.3174
e) 2 drivers
Step-by-step explanation:
Given:
Sample size, n = 5
P = 40% = 0.4
a) Probability that none of the drivers shows evidence of intoxication.



b) Probability that at least one of the drivers shows evidence of intoxication would be:
P(X ≥ 1) = 1 - P(X < 1)
c) The probability that at most two of the drivers show evidence of intoxication.
P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)
d) Probability that more than two of the drivers show evidence of intoxication.
P(x>2) = 1 - P(X ≤ 2)
e) Expected number of intoxicated drivers.
To find this, use:
Sample size multiplied by sample proportion
n * p
= 5 * 0.40
= 2
Expected number of intoxicated drivers would be 2
Since we’ve been given a ratio, 3:8, we can convert that into a fraction and form an equation from it:
= 
The reason the numerator on the second fraction is 27/3 is because the team scored 27 points, not 27 baskets.
Simplify (Also replace the ? with an unknown variable):
= 
Cross multiply:
3*n = 9*8
Simplify:
3n = 72
Divide both sides by 3:
n = 24
The team had 33 three point tries, 9 successes, and 24 fails.
-T.B.