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damaskus [11]
3 years ago
5

Please help. Which polynomial represents the quotient for the division problem shown?

Mathematics
2 answers:
NARA [144]3 years ago
8 0

Answer:

B

Step-by-step explanation:

Just got it on apex

babymother [125]3 years ago
5 0

Answer:the right answer is 3x^2-7x+9; option c

Step-by-step explanation:just did it on apex and option b is incorrect

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Does 26/3 equal 182/21
brilliants [131]

Answer: Yes, they are equal

Step-by-step explanation:

Quick statement: To find equivalent fractions, multiply or divide them by the same number.

In this particular example, you can divide 182 by 7 and get 26 and 21 by 7 to get 3. This symbols that they are equal. If you try the inverse operation (multiplication), you could multiply 26 by 7 and get 182. Same goes for 21 and 3: you multiply 3 by 7 to get 21. Just remember to multiply or divide the two numbers (numerator and denominator) by the same number to get an equivalent fraction.

3 0
4 years ago
Read 2 more answers
Write the name of the period that has the digits 486
kogti [31]
1.       <span>The name of period that has 486 in the given number which is 751 486  is hundreds.
period is considered to a group of places of the digits, like the given number 486 is the group of hundred because the highest number it contains is 400.
=> 400 + 80 + 6
=> 4 hundreds + 8 tens + 6 ones
=> 486
while 751 is the period of hundred thousands.
=> 700 000 + 50 000 + 1 000
=> 751 000

</span>
8 0
3 years ago
Anthony got a new iPhone. He needs to create a 4-digit passcode. How many passcodes can be created if REPETITION OF DIGITS IS AL
Snezhnost [94]
An infinite amount...since there ARE and infinite amount of number in the universe.

1111

2222

3333

4444

5555

6666

7777

8888

9999


1010

1234

4321

5432

2345

5678

8765

0987

7890

4509

9054

Etc
7 0
4 years ago
Si un número divisible entre 3 también es divisible entre 6
Ksivusya [100]

Answer:

es verdad pero 3 nomas puede ser dividido por 3 o 1

Step-by-step explanation:

3 0
3 years ago
How many 3 letter codes are possible using a-j without repeats?
Dennis_Churaev [7]
There are 10 letters in the set {a, b, c, d, e, f, g, h, i, j} which is the pool of letters to choose from when making these three letter codes.

We have 10 choices for slot 1
Then 9 choices for slot 2. This is because we can't reuse the choice for slot 1
Then 8 choices for slot 3

Overall, there are 10*9*8 = 90*8 = 720 different permutations

Answer: 720

Note: you can use the nPr permutation formula with n = 10 and r = 3 to get the same answer
5 0
3 years ago
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