Question

a rope passes over a pulley attached to the ceiling. one end of the rope is held by student a of mass 70 kg, who is at rest on the floor. the opposite end of the rope is held by student b of mass 60 kg, who is suspended at rest above the floor?

Answer 1

Answer:

Student b is suspended at rest above the floor.

Explanation:

Student a and student b are holding the two ends of the rope which passes over a pulley.

The mass of student a = 70 kg

The mass of student b = 60 kg

The tension force acting on the rope is uniform through out the length in this case.

Force due to gravitation:

F = mg

Where,

m is the mass and g is the acceleration due to gravity

Since g is constant for both the students. Thus, F is directly proportional to the mass of the student.

Since the mass of student a is greater than student b. Thus, the force due to the weight of the student a is greater than student b.

Thus, Student a will be at the floor and Student b is suspended at rest above the floor.