2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
i wasn't sure on how to explain it so i just attached ur answer
Answer:
A1=59
A2=85
A3=49
A4=no.because strait lines add up to 180 and it does not
B1=x=133andy=133
B2=53,61,and 56
B3=x=37andy= 37
B4=x=54and y=68
C1=y= 43and x=51
10C9 * (1/5)^9 * (4/5)^1 = 4.096*10^-6
About 4 chances in 1 million.
Answer:
D.
Step-by-step explanation:
I don't know for a fact but I'm pretty sure its D. sorry if its wrong.
Hope this helped.
