Consider triangle XYZ with vertices at points X(1,-3), Y(3,0) and Z(-1,-1). If triangle XYZ is reflected across the line y = 1, then the rule of reflection is
(x,y)→(x,-y+2).
The image X' of point X will have coordinates according to the given rule:
X(1,-3)→X'(1, -(-3)+2)=X'(1,5).
Answer: correct choice is D.
The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
Learn more about The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
Learn more about area here:
brainly.com/question/27683633
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Answer:
The correct answer is D) (-2, -1)
Step-by-step explanation:
In order to solve this system of equations, start by multiplying the entire first equation by 2. Then add the two equations together. This will get the y's to cancel and allow you to solve for x.
-4x + 2y = -10
3x - 2y = 12
---------------------
-x = 2
x = -2
Now that we have the value for x, we can find y by plugging the x value into either equation.
-2x + y = -5
-2(2) + y = -5
-4 + y = -5
y = -1
Answer:
<h3>
- 14</h3>
Step-by-step explanation:
{x - some integer}
2x - the first even integer
2x+2 - the second consecutive even integer
2x+4 - the third consecutive even integer (the largest)
2x + 2x+2 + 2x+4 - the sum of three consecutive even integers
2x + 2x+2 + 2x+4 = -48
6x + 6 = -48
÷3 ÷3
2x + 2 = -16
+2 +2
2x+4 = -14