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3 years ago

Apply the Pythagorean Theorem to find the distance between points A and C.

Mathematics

2 answers:

inna [77]3 years ago

7 0

Hi!

distance from A to the base od C, straight line = 7 units

from the base of C to the point C, straght line = 5 units

$AC^{2} = 7^{2} + 5^{2} \\AC^{2} = 49 + 25\\AC^{2} = 74\\AC = \sqrt{74}\\AC = 8,6$

Hope this helps!

Burka [1]3 years ago

4 0

the horizontal distance ( x direction) from A to C is 7 units and

the vertical distance ( y direction) is 5 units

Applying Pythagoras' Theorem to the right triangle

AC² = 7² + 5² = 49 + 25 = 74, hence

AC = $\sqrt{74}$ = 8.6 units ( to 1 dec. place )

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Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

Xby the power of 5 times y to the power of 6 over 2 by the power of -2 times xby the power of 0times x by the power of 9

mars1129 [50]

Answer:

We have the sentence:

"X by the power of 5 times y to the power of 6 over 2 by the power of -2 times x by the power of 0times x by the power of 9"

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This can be written as:

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"... 2 by the power of -2 times x by the power of 0times x by the power of 9"

This can be written as:

2^(-2)*x^(0)*x^(9)

And we have the quotient between the first thing and the second thing, then the equation is:

$\frac{x^5*y^6}{2^{-2}*x^0*x^9}$

And any number by the power of 0 is equal to 1, then:

x^0 = 1, then we can rewrite the equation as:

$\frac{x^5*y^6}{2^{-2}*x^9}$

We can keep simplifying this.

We know that:

a^(-n) = (1/a)^(n)

Then:

2^(-2) = (1/2)^2 = 1/4

Then we get:

$\frac{x^5*y^6}{2^{-2}*x^9} = \frac{x^5*y^6}{x^9}*4$

And we also know that:

a^n/a^m = a^(n - m)

Then:

$\frac{x^5*y^6}{x^9}*4 = 4*y^6*\frac{x^5}{x^9} = 4*y^6*x^{5 - 9} = 4*y^6*x^{-4} = \frac{4*y^6}{x^4}$

And we can't simplify this anymore.

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2 years ago

Explain why the exponents cannot be added in the product 12^3 x 11^3

cestrela7 [59]

The exponent cannot be added to the product because it stated in the law of exponents. An exponent is simply the shorthand in multiplying your base number. Exponent will give how many times you will multiply the base numbers. It is not possible that you add both exponents in the given situation because they have different value together.
=> 12^3 x 11^3
If we solve this equation following the rule of exponent will get the correct answer:
=> (12 x 12 x 12) x (11 x 11 x 11)
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But if we add the exponent, the answer would be wrong
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3 years ago

Read 2 more answers

What's the area of the triangle with 9mm 76mm 100mm

svlad2 [7]

9514 1404 393

Answer:

342 mm²

Step-by-step explanation:

The triangle shown has a base of 9 mm and a height of 76 mm. Its area is ...

A = 1/2bh

A = (1/2)(9 mm)(76 mm) = 342 mm²

The triangle shown has an area of 342 mm².

_____

<em>Additional comment</em>

The other leg of the right triangle with one leg 76 mm and hypotenuse 100 mm will be about 65 mm. The base shown is 9 mm, so any triangle with the dimensions shown will be a fairly skinny obtuse triangle, not the acute triangle in the picture. (This makes us suspect an error: the 9 mm dimension maybe should be 90 mm.)

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