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LekaFEV [45]
3 years ago
6

‼️‼️‼️‼️ pls, i need help

Mathematics
1 answer:
zepelin [54]3 years ago
7 0
Yo soy muy grande cojones y muy grande Pena!!!!!!
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18.25=4(1.5-3.75x)-.25(4x-5) wat is x?
sdas [7]
The answer is x= - 11/ 16
You can check this by plugging in x for -11/16



5 0
2 years ago
Oliver has three green balls, two red balls , five yellows balls , and four orange balls in a bucket . He randomly chooses one b
Debora [2.8K]

Answer:

The probability that he chooses a yellow ball is 5/14. If he removes all the orange balls, the probability that he will choose a red ball is 2/10.

Step-by-step explanation:

Simple logic.

7 0
3 years ago
A picture has a height that is 2 times it’s width . It is to be enlarged to an area of 128 in 2
morpeh [17]

9514 1404 393

Answer:

  8 in by 16 in

Step-by-step explanation:

In your equation, we presume that x represents the width. Solving for x, we have ...

  2x² = 128 . . . . . . given equation

  x² = 64 . . . . . . . . divide by 2

  x = √64 = 8 . . . . square root

The enlargement will be 8 inches by 16 inches.

8 0
2 years ago
What is the greatest common factor of the following monomials: 12g^5h^4 g^5h^2
muminat

Answer:

g^5h^2

Step-by-step explanation:

12g^5h^4, g^5h^2

This is one way of doing it. Break down every number and every variable into a product of the simplest factors. Then see how many of each factor appear in both monomials.

12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h

g^5h^2 = g * g * g * g * g * h * h

So far you see every single prime factor of each monomial.

Now I will mark the ones that are present in both. Those are the common factors.

12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h

g^5h^2 = g * g * g * g * g * h * h

The greatest common factor is the product of all the factors that appear in both monomials.

GCF = g * g * g * g * g * h * h = g^5h^2

6 0
2 years ago
Lf a, 3, b, 12, c are in G.P then find the value of a, b and c. plz help me AsAp!!!​
AlexFokin [52]

Answer:

hope this helps...

Step-by-step explanation:

If this helped you please comment me...

3 0
3 years ago
Read 2 more answers
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