One number is 26 the other is 23
x+y=49
Y=x+3,X (now substitute it in the equation)
x+3+x=49
2x+3=49
2x=46. X=23
Y=x+3. Y=23+3 =26 for checking 23+26=49
Answer:
Distance of JK = 15 unit
Step-by-step explanation:
Given:
J(4,8)
K(-1,-2)
Find:
Distance of JK
Computation:
Distance = √(x₂-x₁)² + (y₂-y₁)²
Distance of JK = √(-1-4)² + (-2-8)²
Distance of JK = √25 + 100
Distance of JK = √125
Distance of JK = 15 unit
