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3 years ago

A baseball team lost 4 more games than it won. If the team played 46 games, how many did it lose? How many did it win?

Mathematics

1 answer:

blsea [12.9K]3 years ago

4 0

The team won 27 games and lost 19

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Pls help by today :) ill give brainliest when I can

horrorfan [7]

Answer:

B and C

Step-by-step explanation:

2/3 = 6/9

and

1/2 = 4/8

6 0

2 years ago

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Suppose that 21 out of 25 people who apply to a certain college are accepted. What percentage of people who apply are accepted t

IgorC [24]

Answer:

84%

Step-by-step explanation:

The first step is to write 21 as a fraction of 25, which is simply

21/25

Now we just need to convert this fraction to a percentage :

21/25 = 84

So, 21 is 84% of 25

8 0

3 years ago

Exercise 6.13 presents the results of a poll evaluating support for the health care public option in 2009, reporting that 52% of

sleet_krkn [62]

Answer:

A sample size of 6755 or higher would be appropriate.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error M is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

52% of Independents in the sample opposed the public option.

This means that $p = 0.52$

If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?

Sample size of size n or higher when $M = 0.01$ . So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.645\sqrt{\frac{0.52*0.48}{n}}$

$0.01\sqrt{n} = 0.8218$

$\sqrt{n} = \frac{0.8218}{0.01}$

$\sqrt{n} = 82.18$

$\sqrt{n}^{2} = (82.18)^{2}$

$n = 6754.2$

A sample size of 6755 or higher would be appropriate.

3 0

3 years ago

WILL GIVE YOU BRAINLIEST!! (only answer if u know for sure) A coin is flipped 20 times. 13 times the coin lands on heads. What i

tangare [24]

there is a 50% chance of landing on either heads or tails

3 0

3 years ago

Round your answer to the nearest hundredth.

Dmitry_Shevchenko [17]

tan 35 = BC / 2

0.700 = bc/2

bc = 1.4

3 0

2 years ago

Read 2 more answers