The figure below is a scale drawing of Quinto's bedroom. The scale used to create the drawing is 1/2 inch = 4 feet. What is the
approximate area of Quinto's bedroom. p.s.use attachment to find the question for the image
1 answer:
We know that
the scale is <span>is 1/2 inch = 4 feet
using a graph tool
</span><span>the approximate measurements in the drawing are
</span>5 cm x 4 cm
convert to in
5/2.54--------> 1.97 in
4/2.54------> 1.57 in
convert drawing to actual
if 0.5 in---------> 4 ft
1.97in-------> X
X=1.97*4/0.5------> X=15.76 ft
if 0.5 in---------> 4 ft
1.57 in-------> X
X=1.57*4/0.5------> X=12.56 ft
<span>the approximate area of Quinto's bedroom is 12.56*15.76=197.95 ft</span>²
the answer is
the option C)192 ft²
the scale is <span>is 1/2 inch = 4 feet
using a graph tool
</span><span>the approximate measurements in the drawing are
</span>5 cm x 4 cm
convert to in
5/2.54--------> 1.97 in
4/2.54------> 1.57 in
convert drawing to actual
if 0.5 in---------> 4 ft
1.97in-------> X
X=1.97*4/0.5------> X=15.76 ft
if 0.5 in---------> 4 ft
1.57 in-------> X
X=1.57*4/0.5------> X=12.56 ft
<span>the approximate area of Quinto's bedroom is 12.56*15.76=197.95 ft</span>²
the answer is
the option C)192 ft²
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Answer:
a)
The null hypothesis is:
The alternative hypothesis is:
b) For men is of 0.49 and for women is of 0.36.
c) The p-value of the test is 0.0039 < 0.01, which means that the results are statistically significant so that you can conclude a greater proportion of men expect to get a raise or a promotion this year.
Step-by-step explanation:
Before solving this question, we need to understand the central limit theorem and subtraction of normal variables.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean and standard deviation
Subtraction between normal variables:
When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.
Men:
98 out of 200, so:
Women:
72 out of 200, so:
a. State the hypothesis test in terms of the population proportion of men and the population proportion of women.
At the null hypothesis, we test if the proportion are similar, that is, if the subtraction of the proportions is 0, so:
At the alternative hypothesis, we test if the proportion of men is greater, that is, the subtraction is greater than 0, so:
b. What is the sample proportion for men? For women?
For men is of 0.49 and for women is of 0.36.
c. Use α= 0.01 level of significance. What is the p-value and what is your conclusion?
From the sample, we have that:
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis, and s is the standard error, so:
P-value of the test and decision:
The p-value of the test is the probability of finding a difference above 0.13, which is the p-value of z = 2.66.
Looking at the z-table, z = 2.66 has a p-value of 0.9961.
1 - 0.9961 = 0.0039.
The p-value of the test is 0.0039 < 0.01, which means that the results are statistically significant so that you can conclude a greater proportion of men expect to get a raise or a promotion this year.