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professor190 [17]
3 years ago
6

Find the limit. lim t→0 5et − 5 t , 1 + t − 1 t , 4 1 + t

Mathematics
1 answer:
sergeinik [125]3 years ago
5 0

Calculator can help you

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1/4x+4is greater than or equal to 3
goldfiish [28.3K]

1/4x+4is greater than or equal to 3


1/4x=>-4+3


1/4x=>-1


(4)1/4x=>-1(4)


X=> -4

5 0
3 years ago
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
3 years ago
¿give me the answer please?
nevsk [136]

Answer:

the volume is 60 cm cubed

Step-by-step explanation:

(5 x 8) / 2 x 3

5 x 8 = 40

40 / 2 = 20

20 x  3 = 60

6 0
2 years ago
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Erome is cooking dinner. He needs 8 ounces of broccoli for each person.
masha68 [24]
Answer for part B is 4
4 0
3 years ago
William earns $2,400.00 each month. His current monthly expenses are $1,910.00. This month, he plans to pay a little extra to hi
Marianna [84]

Answer:

b

Step-by-step explanation:

2400-1910=490

5 0
3 years ago
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