Answer:
25%
Step-by-step explanation:
Discount = 1600 - 1200 = 400
Percentage discount
![= \frac{400}{1600} \times 100 \\ \\ = \frac{400}{16} \\ \\ = 25\%](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B400%7D%7B1600%7D%20%20%5Ctimes%20100%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B400%7D%7B16%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%2025%5C%25)
Let the numbers be n, n+2, n+4
Sum equals too= 13+2(n+4), which is 2n+21
a) Equation--> n+n+2+n+4= 2n+21
b) Solution--> 3n+6= 2n+21
=> n= 15
c) Second number--> 17 (15+2)
Third number--> 19 (15+4)
d) 15+15+2+15+4=30+21
=> 51= 51
So, the equation is true.
And pls mark me brainliesttt :)))
Answer: to solve the 3 unknown variables X, Y and Z in a set of 3 equations. Each equation has containing the unknown variables X, Y and Z. This 3 equations 3 unknown variables solver computes the output value of the variables X and Y with respect to the input values of X, Y and Z coefficients. In mathematic calculations, there are many situation arises where the usage of equation containing 3 unknown variables need to be solved prior to go further with the calculations. Therefore when it comes to online calculation, this Find the value of X, Y and Z calculator is an essential tool to assist you to find out the variable values given in the equation.
Step-by-step explanation: X = 2
Y = -1
Z = 1
Answer:
Therefore,
Dimensions of the Original Square is
![x =11\ m](https://tex.z-dn.net/?f=x%20%3D11%5C%20m)
Step-by-step explanation:
Given:
Let the side of Square be "x" meter
Then the Dimensions of a Rectangle is formed by adding 6 m to one side and 3 m to the other side wil be.
![Length = x+6\\\\Width=x+3](https://tex.z-dn.net/?f=Length%20%3D%20x%2B6%5C%5C%5C%5CWidth%3Dx%2B3)
Area of Rectangle =238 m²
To Find:
x = ? (Dimension of Original Square)
Solution:
Area of Rectangle is given by
![\textrm{Area of Rectangle}=Length\times Width](https://tex.z-dn.net/?f=%5Ctextrm%7BArea%20of%20Rectangle%7D%3DLength%5Ctimes%20Width)
Substituting the values we get
![238=(x+6)\times (x+3)](https://tex.z-dn.net/?f=238%3D%28x%2B6%29%5Ctimes%20%28x%2B3%29)
Opening the Parenthesis we get
......Which is Quadratic equation
On Factorizing and Splitting the middle term we get
![x^{2}+20x-11x-220=0\\\\x(x+20)-11(x+20)=0\\\\(x+20)(x-11)=0\\\\x+20=0\ or\ x-11=0\\\\x=-20\ or\ x=11](https://tex.z-dn.net/?f=x%5E%7B2%7D%2B20x-11x-220%3D0%5C%5C%5C%5Cx%28x%2B20%29-11%28x%2B20%29%3D0%5C%5C%5C%5C%28x%2B20%29%28x-11%29%3D0%5C%5C%5C%5Cx%2B20%3D0%5C%20or%5C%20x-11%3D0%5C%5C%5C%5Cx%3D-20%5C%20or%5C%20x%3D11)
As distance cannot be negative therefore,
![x =11](https://tex.z-dn.net/?f=x%20%3D11)
Therefore,
Dimensions of the Original Square is
![x =11\ m](https://tex.z-dn.net/?f=x%20%3D11%5C%20m)
Answer:
Hello
Step-by-step explanation:
The domain is limited with 2 lines parallel: -1 ≤ x ≤ 1
and the disk ? (inside of a circle) of center (0,0) and radius 2
![dom\ f(x,y)=\{(x,y) \in \mathbb{R} ^2 | \ -1\leq x \leq -1\ and \ ( -\sqrt{4-x^2} \leq \ y \leq \sqrt{4-x^2}\ ) \ \}\\](https://tex.z-dn.net/?f=dom%5C%20f%28x%2Cy%29%3D%5C%7B%28x%2Cy%29%20%5Cin%20%5Cmathbb%7BR%7D%20%5E2%20%7C%20%5C%20-1%5Cleq%20x%20%5Cleq%20-1%5C%20and%20%5C%20%28%20-%5Csqrt%7B4-x%5E2%7D%20%20%5Cleq%20%5C%20y%20%20%5Cleq%20%5Csqrt%7B4-x%5E2%7D%5C%20%20%29%20%5C%20%5C%7D%5C%5C)