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Slav-nsk [51]
3 years ago
9

Which of the following is the rational exponent expression of sixth root of f?

Mathematics
1 answer:
vitfil [10]3 years ago
5 0

Answer:

\sqrt[6]{f} = f^{1/6}

Step-by-step explanation:

the law in its form is \sqrt[n]{a}^{m} = a^{m/n}

therefore \sqrt[6]{f} = fx^{1/6} \\

You might be interested in
What is the Slope and y intercept
Inessa [10]

Answer:

The slope is .075 and the y intercept is -.125

Step-by-step explanation:

8y = .2(3x -5)

Distribute the .2

8y = .6x - 1

Divide by 8

8y/8 = .6x/8 -1/8

y = .075x -.125

This is in slope intercept form  y= mx+b  where m is the slope and b is the y intercept.

The slope is .075 and the y intercept is -.125

5 0
3 years ago
Euclidean Geometry<br>which distance measures 7 units​
belka [17]

Answer:

Whichever distance you can count the metric units and see that the x value is 7 on

Step-by-step explanation:

Whichever distance you can count the metric units and see that the x value is 7 on

6 0
3 years ago
Can someone help me with this, please? I'm not sure how to solve this.
bazaltina [42]

Answer:

11.) 10w^2 + 43w + 21.

12.) -15y^2 - 2y + 8

Check the explanation for details

Step-by-step explanation:

11.) You are meant to multiply each row by both columns. For instance, multiply 5w by 2w and 7 you will get 10 w^2 and 35 w

Also, multiply 3 by both 2w and 7 you will get 6w and 21. Therefore,

Expansion of ( 5w + 3 )( 2w + 7 ) will produce 10w^2 + 37w + 6w + 21

= 10w^2 + 43w + 21.

12.) Repeat the same process by multiplying row by column.

Multiply -3y by 5y and 4 you will get -15y^2 and -12y.

Also, multiply 2 by same 5y and 4. You will get 10y and 8

Therefore, the expansion of

( -3y + 2 )( 5y + 4 ) will be

-15y^2 - 12y + 10y + 8

-15y^2 - 2y + 8

4 0
3 years ago
Consider the function and its inverse.
Ber [7]

Answer:

The domain of f(x) is restricted to x\leq 0, and the domain of f^{-1}(x) is restricted to x\geq 4.

Step-by-step explanation:

From Function Theory we know that domain of a function is the set of values such that an image exist. Let f(x) = x^{2}+4 and f^{-1}(x) = \sqrt{x-4} the function and its inverse, respectively.

At first glance we notice that function is a second order polynomial and every polinomial is a continuous function and therefore, there exists an image for every element of domain.

But domain of its inverse is restricted to every value of x so that x-4 \geq 0, which means that x\geq 4.

Finally, we concluded that following answer offers the best approximation to our result:

The domain of f(x) is restricted to x\leq 0, and the domain of f^{-1}(x) is restricted to x\geq 4.

6 0
3 years ago
Freddy is on a nature hike. He hikes west 4 miles, and then he turns due north and hikes for 2 miles. It is getting dark and Fre
melomori [17]

The direct path back forms a right triangle. Use the Pythagorean theorem:

X = sqrt(4^2 + 2^2)

X = sqrt(16 + 4)

X = sqrt(20) = 2sqrt(5)

X = 4.472

Round the answer as needed.

7 0
2 years ago
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