In triangles DEF and OPQ, ∠D ≅ ∠O, ∠F ≅ ∠Q, and segment DF ≅ segment OQ; this is not sufficient to prove triangles DEF and OPQ congruent through SAS
<h3>What are
congruent triangles?</h3>
Two triangles are said to be congruent if they have the same shape, all their corresponding angles as well as sides must also be congruent to each other.
Two triangles are congruent using the side - angle - side congruency if two sides and an included angle of one triangle is congruent to that of another triangle.
In triangles DEF and OPQ, ∠D ≅ ∠O, ∠F ≅ ∠Q, and segment DF ≅ segment OQ; this is not sufficient to prove triangles DEF and OPQ congruent through SAS
Find out more on congruent triangle at: brainly.com/question/1675117
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To get rid of
, you have to take the third root of both sides:
![\sqrt[3]{x^{3}} = \sqrt[3]{1}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B1%7D%20)
But that won't help you with understanding the problem. It is better to write
as a product of 2 polynomials:
From this we know, that
is the solution. Another solutions (complex roots) are the roots of quadratic equation.
Answer:
2.83
Step-by-step explanation:
85 divided by 30 = 2.83
.25 times 2.83 = .70 cents
Step-by-step explanation:
step one:
given that the sample space is
red, yellow, green, white, and black. i.e (1+1+1+1+1)= 5
the sample size is 5
the probability of picking a colored card at random is
Pr(a colored card)= 1/5
step two:
without replacement, after the first event, the sample size is now 4
then the probability of picking a colored card at random is
Pr(a colored card)= 1/4
