All categories

3 years ago

In ΔEFG, the measure of ∠G=90°, EG = 11, FE = 61, and GF = 60. What ratio represents the sine of ∠F?

Mathematics

1 answer:

lapo4ka [179]3 years ago

6 0

Answer:

sinF = $\frac{11}{61}$

Step-by-step explanation:

sinF = $\frac{opposite}{hypotenuse}$ = $\frac{EG}{FE}$ = $\frac{11}{61}$

You might be interested in

What is the third quartile, Q3, of the following distribution?

GREYUIT [131]

Answer:

The third quartile is:

$Q_3=29$

Step-by-step explanation:

First organize the data from lowest to highest

4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44

Notice that we have a quantity of n = 20 data

Use the following formula to calculate the third quartile $Q_3$

For a set of n data organized in the form:

$x_1, x_2, x_3, ..., x_n$

The third quartile is $Q_3$ :

$Q_3=x_{\frac{3}{4}(n+1)}$

With n=20

$Q_3=x_{\frac{3}{4}(20+1)}$

$Q_3=x_{15.75}$

The third quartile is between $x_{15}=29$ and $x_{16}=29$

Then

$Q_3 =x_{15} + 0.75*(x_{16}- x_{15})$

$Q_3 =29 + 0.75*(29- 29)\\\\Q_3 =29$

5 0

3 years ago

Read 2 more answers

Who is sacatoa joe in geometry

valkas [14]

I think that you are mistaking the memory tool for something else
or a math book is trying to make math cute by calling them 'socatoa joe' and 'mr. pi' and such

anyway, SOH, CAH, TOA is the way to remember
Sine=oposite/hypotonuse
Cosine=adjacent/hypotonuse
Tangent=oposite/adjacent

(oposite side=side oposite the angle
adjacent is the side touching the angle that is not they hypotonuse
and of course the hypotonuse is the longest side aka, side oposite right angle)

3 0

4 years ago

Find the volume.<br> Area = 16.4 cm²<br> 8.1 cm<br> cm³

Tasya [4]

Answer:

132.84 is the answer as volume is area times length

6 0

2 years ago

The price of a certain computer stock t days after it is issued for sale is p(t)=100+20t−6t^2 dollars. The price of the stock in

Elanso [62]

Answer:

0 < t < $\frac{5}{3}$

After 1.67 days the stocks would be sold out.

Step-by-step explanation:

The price of a certain computer stock after t days is modeled by

p(t) = 100 + 20t - 6t²

Now we will take the derivative of the given function and equate it to zero to find the critical points,

p'(t) = 20 - 12t = 0

t = $\frac{20}{12}$

t = $\frac{5}{3}$ days

Therefore, there are two intervals in which the given function is defined

(0, $\frac{5}{3}$ ) and ( $\frac{5}{3}$ , ∞)

For the interval (0, $\frac{5}{3}$ ),

p'(1) = 20 - 12(1) = 20

For the interval ( $\frac{5}{3}$ , ∞),

p'(2) = 20 - 12(2) = -4

Positive value of p'(t) in the interval (0, $\frac{5}{3}$ ) indicates that the function is increasing.

0 < t < $\frac{5}{3}$

Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.

7 0

3 years ago

Suppose you connect the points on the graph in the example, what would the graph look like?<br>

aliya0001 [1]

Answer:

Your graph would look like lines going up and up and up

Step-by-step explanation:

Why you ask? Well, because the graph shown here is going by the factors of 6. And the factors of 6 are pretty high, which means it would be going up like a twisted line going right ot left depending which way you look at it. It would be going up and up because like 18 times 6 is 108 and 20 times 6 is 120.

3 0

3 years ago