Answer:
2 units.
Step-by-step explanation:
In this question we use the Pythagorean theorem which is shown below:
Given that
The right triangle OMP
The hypotenuse i.e OM is the circle radius =5 units.
The segment MP = 4 units length
Therefore



So OP is 3
Now as we can see that ON is also circle radius so it would be 5 units
And,
ON = OP + PN
So,
PN is
= ON - OP
= 5 units - 3 units
= 2 units
Answer:
$3530.3541
Step-by-step explanation:
Given that:
Principal = 2200
Interest rate compounded annually (r) = 3%
Time (t) = 16 years
Using the compound interest formula :
A = P(1 + r/n)^n*t
A = final amount
n = number of times interest is applied per period
A = 2200(1 + 0.03)^16
A = 2200(1.03)^16
A = 2200 * 1.60470643909878751793
A = $3530.3541
Hence, amount in account on his 16th birthday will be $3530. 3541
Answer:
sorry.......dud.....
Step-by-step explanation:
hope some one will help you........
Answer:
1) X stands for individual acts and y, group acts. 2) Each scenario describes a different period in minutes, but each one respecting their different amounts (individual and group acts). 3) 
Step-by-step explanation:
Completing with what was found:
<em> 1) Here is a summary of the scenario your classmate presented for the talent show:Main show The main show will last two hours and will include twelve individual acts and six group acts.Final show The final show will last 30 minutes and will include the top four individual acts and the top group act.The equations he came up with are: 12x+ 6y= 120, 4x+ y= 30</em>
1. What do x and y represent in this situation?
X stands for individual acts and y, group acts.
Besides that, In the system of equation, they represent the time for x, and the time for y.
2. Do you agree that your classmate set up the equations correctly? Explain why or why not.
Yes, that's right. Each scenario describes a different period in minutes, but each one respecting their different amounts (individual and group acts). Either for 120 minutes or 30 minutes length. And their sum totalizing the whole period.
3. Solving the system by Elimination
