Your answer is x = 2.92 = 3.
To answer this question you need to use trigonometry, so the first step is to identify the hypotenuse, opposite, and adjacent.
Because the angle 73 is in the bottom corner next to the length x, we know that the length x is the adjacent. The length 10 is opposite the right angle so this must be the hypotenuse.
We know that cos(θ) = adjacent/hypotenuse, so we can substitute in what we know:
cos(θ) = adjacent/hypotenuse
cos(73) = x/10
Now we can rearrange for x:
cos(73) = x/10
× 10
cos(73) × 10 = x
Finally we just type this into the calculator and get the answer as 2.92 or 3.
I hope this helps!
Answer:
$4.80.
Step-by-step explanation:
hope this helps
The answer is 5.13 in²
Step 1. Calculate the diameter of the circle (d).
Step 2. Calculate the radius of the circle (r).
Step 3. Calculate the area of the circle (A1).
Step 4. Calculate the area of the square (A2).
Step 5. Calculate the difference between two areas (A1 - A2) and divide it by 4 (because there are total 4 segments) to get <span>the area of one segment formed by a square with sides of 6" inscribed in a circle.
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Step 1:
The diameter (d) of the circle is actually the diagonal (D) of the square inscribed in the circle. The diagonal (D) of the square with side a is:
D = a√2 (ratio of 1:1:√2 means side a : side a : diagonal D = 1 : 1 : √2)
If a = 6 in, then D = 6√2 in.
d = D = 6√2 in
Step 2.
The radius (r) of the circle is half of its diameter (d):
r = d/2 = 6√2 / 2 = 3√2 in
Step 3.
The area of the circle (A1) is:
A = π * r²
A = 3.14 * (3√2)² = 3.14 * 3² * (√2)² = 3.14 * 9 * 2 = 56.52 in²
Step 4.
The area of the square (A2) is:
A2 = a²
A2 = 6² = 36 in²
Step 5:
(A1 - A2)/4 = (56.52 - 36)/4 = 20.52/4 = 5.13 in²
Answer:
it would be probably the letter M
QUESTION 33
The length of the legs of the right triangle are given as,
6 centimeters and 8 centimeters.
The length of the hypotenuse can be found using the Pythagoras Theorem.
Answer: C
QUESTION 34
The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.
The length of the other leg can be found using the Pythagoras Theorem,
Answer:B
QUESTION 35.
We want to find the distance between,
(2,-1) and (-1,3).
Recall the distance formula,
Substitute the values to get,
Answer: 5 units.
QUESTION 36
We want to find the distance between,
(2,2) and (-3,-3).
We use the distance formula again,
Answer: D
