A 6 cm long spring extends to 9 cm when a 1 kg load is suspended from it. What would be its length if a 2 kg load were suspended
1 answer:
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Answer:
Step-by-step explanation:
Pythagorean theorem
hip² = op² + ad²
17² = x² + 8²
x² = 17² - 8²
The given equation is
We need to solve the equation for q.
<u>Value of q:</u>
The value of q can be determined by solving the equation for q.
Thus, subtracting both sides of the equation by r, we get;
Now, dividing both sides of the equation by b, we have;
Simplifying the terms, we get;
Therefore, the value of q is
Hence, Option B is the correct answer.
10 more times
On Monday the rover needed to charge 22 times and on Tuesday 12 times.
So the answer is 22-12=10
On Monday the rover needed to charge 22 times and on Tuesday 12 times.
So the answer is 22-12=10