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dangina [55]
4 years ago
13

A 6 cm long spring extends to 9 cm when a 1 kg load is suspended from it. What would be its length if a 2 kg load were suspended

from it?
Mathematics
1 answer:
vampirchik [111]4 years ago
4 0

Answer:

12 cm

Step-by-step explanation:

To calculate the length of a spring with a 2 kg load, compare the displacement of a 1 kg load and adjust accordingly.

When a 1 kg load is suspended from the spring, the spring which is 6 cm stretches to 9 cm. This is 3 cm longer due to the weight. If you attach a weight which is twice as much then the displacement will be twice as much. Instead of stretching an additional 3 cm, it will stretch 2*3 = 6 cm. Add this to the length of the spring and it stretches in total 6 + 6 = 12 cm.

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Find the surface area of the rectangular prism. justify your answer 3ft, 2ft, 4ft
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Answer: SA=52\ ft^2

Step-by-step explanation:

The surface area of a rectangular prism can be calculated with the following formula:

SA = 2wl + 2lh + 2hw

Where "l" is the length of the rectangular prism, "w" is the width and "h" is the height.

In this case you can say that the length, the width and the heigth of this rectangular prism, are the following:

l=4\ ft\\\\w=2\ ft\\\\h=3\ ft

Knowing these values, you can substitute them into the formula shown before:

SA = 2wl + 2lh + 2hw\\\\SA = 2(2\ ft)(4\ ft) + 2(4\ ft)(3\ ft)+ 2(3\ ft)(2\ ft)

Finally, you must evaluate in order to calculate the surface area of the rectangular prism.

You get that this is:

SA=2(8\ ft^2)+2(12\ ft^2)+2(6\ ft^2)\\\\SA=16\ ft^2+24\ ft^2+12\ ft^2\\\\SA=52\ ft^2

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