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denis23 [38]
3 years ago
6

Which expression is equivalent to (sin x + 1)(sin x − 1)? A. cos2x B. -cos2x C. cos2x + 1 D. cos2x − 1 E. -cos2x + 1

Mathematics
1 answer:
Semenov [28]3 years ago
4 0

ANSWER

B.

- \cos^{2} x

EXPLANATION

The given expression is

(sin x + 1)(sin x − 1)

Note that:

(x + 1)(x - 1) =  {x}^{2}  - 1

This implies that,

( \sin \: x + 1)( \sin \: x - 1)  =   \sin^{2} x - 1

We can factor -1 on the right hand side to get,

( \sin \: x + 1)( \sin \: x - 1)  =    - (1 - \sin^{2} x )

Note that from the Pythagorean Identity

1 - \sin^{2} x = \cos^{2} x

We apply this identity to obtain:

( \sin \: x + 1)( \sin \: x - 1)  = - \cos^{2} x

The correct choice is B

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Answer: x = {-4, -1, 2}

<u>Step-by-step explanation:</u>

        q                     p

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-1  |  1     3     -6     -8

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      1      2    -8      0

(x + 1)(x² + 2x - 8)  = 0

Next, factor the polynomial:

(x + 1)(x + 4)(x - 2)  = 0  

x + 1 = 0        x + 4 = 0         x - 2 = 0

x = -1              x = -4               x = 2

 


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