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erica [24]
3 years ago
5

Can you please help? I will reward points! And I might give thanks also brainlest

Mathematics
2 answers:
stealth61 [152]3 years ago
5 0
A is your answer. It is not a combination that can be used to make the change the coach needs. 
I hope this helps!
Genrish500 [490]3 years ago
3 0
It  would be B because he pays 30

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Two similar solids have surface areas of 48cm and 108cm respectively.find the volume of the smaller solid if the bigger one has
mestny [16]

Answer:

The volume of the smaller solid is 72 cm.

Step-by-step explanation:

Given that two similar solids have surface areas of 48cm and 108cm respectively, to find the volume of the smaller solid if the bigger one has a volume of 162cm the following calculation must be performed:

108 = 162

48 = X

48 x 162/108 = X

7776/108 = X

72 = X

Therefore, the volume of the smaller solid is 72 cm.

7 0
3 years ago
Evaluate 4x + 5y , when x = 7 and y = 10
Sladkaya [172]

Hi ;-)

x=7 \ and \ y=10\\\\4x+5y=4\cdot7+5\cdot10=28+50=\boxed{78}

5 0
3 years ago
Read 2 more answers
What is a counterexample of the following conjecture any number that is divisible by 3 is also divisible by 6
Bess [88]

Any odd multiple of 3 would be the counterexample of the given conjecture.

That is 3(2n - 1), for any natural number n, will be divisible by 3 but not divisible by 6 as 2 is not a factor.

<u>Examples:</u>

3(3) = 9

3(5) = 15

3(7) = 21 are some examples.

6 0
3 years ago
I just need help with 15
Iteru [2.4K]

Answer:

The answer is survey five randomly selected students from every homeroom

Step-by-step explanation:

hope it helps

4 0
3 years ago
Find the equation of the circle whose center and radius are given.<br> center (5,6), radius = 3
MArishka [77]

Answer:

(x - 5)² + (y - 6)² = 9

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (5, 6) and r = 3, thus

(x - 5)² + (y - 6)² = 9 ← equation of circle

4 0
3 years ago
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