All categories

2 years ago

5. Please write the equation of a line in y=mx+b format. Find the SLOPE first then find the Y-INTERCEPT (b) Your answer

Mathematics

1 answer:

castortr0y [4]2 years ago

5 0

Answer:

y = $\frac{5}{3}x-1$

Step-by-step explanation:

Let the equation of the line is,

y = mx + b

Here m = slope of the line

b = y-intercept

Slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is,

m = $\frac{y_2-y_1}{x_2-x_1}$

From the graph attached,

Since, the given line passes through (0, -1) and (3, 4),

Slope 'm' = $\frac{4+1}{3-0}$

m = $\frac{5}{3}$

y - intercept 'b' = -1

Therefore, equation of the line will be,

y = $\frac{5}{3}x-1$

You might be interested in

The sum of twice a number p and 6 is 12

madreJ [45]

2x + 6 hope this helps

3 0

2 years ago

Find The Five<br> Rational number<br> Between<br>-3/2 and 5/3

Umnica [9.8K]

here is your answer

1.61 , 1.6245, 1.512, 1.432, 1.32456

Step-by-step explanation:

covert fraction to decimal we get,

-3/2 = -1.5 and 5/3 = 1.70

and any number that lies between these two numbers which is terminating and non repeating or non terminating repeating.. that are the numbers that you need.

3 0

3 years ago

What is the aswer ??????

Rom4ik [11]

Answer:

A is correct don't you know

8 0

2 years ago

Read 2 more answers

What is the domain for each function below? Choose the correct inequality symbol from the drop down menu and fill in the blank w

erik [133]

Answer:

$x \le 3$

$x \ge 0$

Step-by-step explanation:

The functions, missing from the question are:

$f(x) = \sqrt{3 - x$

$f(x) = \sqrt{3 x$

Required

Determine the domain

To get the domain, means we want to get the possible values of x.

(a)

$f(x) = \sqrt{3 - x$

Equate 3 - x to 0

$3 - x = 0$

Solve for x

$-x = -3$

$x = 3$

From the calculated value of x above;

When x exceeds 3; f(x) = undefined

So: the domain is:

$x \le 3$

(b)

$f(x) = \sqrt{3x$

Equate 3x to 0

$3x = 0$

Solve for x

$x = 0$

From the calculated value of x above;

When x falls below 0; f(x) = undefined

So: the domain is:

$x \ge 0$

4 0

2 years ago

Can someone find r please

katrin2010 [14]

Answer:

$r = 3 \times \sqrt{2}$

Step-by-step explanation:

The area of the square is 36.

A = s^2

36 = s^2

s = sqrt(36)

s = 6

The side of the square has length 6.

All sides of a square are congruent, so all sides have length 6.

If you extend segment JO to point L, you end up with segment JL which is a diameter of the circle and the diagonal of the square. We can use the Pythagorean theorem using two sides if the square as legs and the diagonal of the square as the hypotenuse of a right triangle.

a^2 + b^2 = c^2

6^2 + 6^2 = c^2

36 + 36 = c^2

c^2 = 72

$c = \sqrt{72}$