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3 years ago

How can you translate the word phrase into verbal expression eight less than the quotient of x and three

Mathematics

1 answer:

Vladimir [108]3 years ago

3 0

X divided by 3 or X/3 minus 8

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How do I find the area

inn [45]

Wasssaa,

Steps:

To find the area of a triangle you multiply the base times the height, in this case the is (19m)
and the height is (11m), after you multipy those numbers you divide by (2)
$(19m \times 11m) \div 2$
$\frac{209 }{2}$

Answer:
$104.5sq \: m$
Hope this helped you
:D

8 0

3 years ago

posledela

Answer:

outfit costs 81 dollars

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Translate radical expressions into expressions with rational exponents, and vice versa. Simplify numerical

dmitriy555 [2]

Answer:

a) ( $\sqrt[n]{x}$ ) the n will be 5 the x will be (-32/243)^2.

b) written the same as a. except the c will replace the n and x will be (2y)^b.

c) the answer will be 0.4^3.

d) the answer would be (st)^v/u.

Hope this helps!

Brainliest?

3 0

3 years ago

A rectangular game board measures 126 centimeters by 90 centimeters. The game board is divided into small squares of equal size.

Ivahew [28]

The area of your game board is = 126 * 90 = 11340 cm^2;
A small suares has x^2 his area; where x measure his length;

Prime factorization

11340 | 2
5670 | 2
2835 | 5
567 | 3
189 | 3
63 | 3
21 | 3
7 | 7
1

11340 = 2^2 * 3^4 * 5 * 7 = 2^2 * ( 3^2 ) ^ 2 * 5 * 7 = 18^2 * 5 * 7

We observ that the possible length of the side is 18( we have 35 small squares ).

8 0

3 years ago

A thermometer is taken from an inside room to the outside, where the air temperature is 20° f. after 1 minute the thermometer re

fomenos

The change in the temperature is proportional to the difference in temperatures. Let's call the initial temperature of the room and the thermometer $E_0$ and the current temperature $E(t)$ where $t$ is the elapsed time in minutes. The outside temperature is 20 F.

Newton's Law of Cooling:

$E(t) - 20 = (E_0 - 20) e^{- k t}$

We're given $E(1)=70 \textrm{ and } E(5)=45$

$70-20 = (E_0 - 20) e^{-k}$

$45-20 =(E_0 - 20) e^{-5k}$

Dividing,

$\dfrac{50}{25}=e^{4k}$

$k = \dfrac 1 4 \ln 2$

Now,

$E(t) - 20 = (E_0 - 20) e^{- k t}$

$E_0 = 20 + (E(t) - 20)e^{k t}$

$E_0 = 20 + (E(1) - 20)e^{k}$

$E_0 = 20 + (70 - 20)e^{\ln 2/4}$

$E_0 = 20 + 50 \cdot 2^{1/4} \approx 79.46 \textrm{ degrees F}$

3 0

3 years ago