Answer:
No invariant point
Step-by-step explanation:
Hello!
When we translate a form, in this case a polygon We must observe the direction of the vector. Since our vector is:
1) Let's apply that translation to this polygon, a square. Check it below:
2) The invariant points are the points that didn't change after the transformation, simply put the points that haven't changed.
Examining the graph, we can see that no, there is not an invariant point, after the translation. There is no common point that belongs to OABC and O'A'B'C' simultaneously. All points moved.
The probability of picking a nickel first would be: 4/10
The probability of picking a dime first would be: 6/10
Answer: as a number?
Step-by-step explanation:
Be a little more specific
The congruency statement which is true among the answer choices is;
- On a coordinate plane, triangle G H I is rotated 90 degrees clockwise and then is reflected over the y-axis.
- Triangle G H I is congruent to triangle G double-prime H double-prime I double-prime.
<h3>Which congruency statement is true?</h3>
According to the task content, the initial transformation is; Triangle GHI is rotated 90Degrees clockwise and then reflected over the y-axis.
On this note, the congruency which are true regarding the transformation are;
- On a coordinate plane, triangle G H I is rotated 90 degrees clockwise and then is reflected over the y-axis.
- Triangle G H I is congruent to triangle G double-prime H double-prime I double-prime.
This follows from the fact that the transformation.does not involved dilation by means of a scale factor and hence, size remains equal and all angle measures remain the same.
Read more on triangle congruence;
brainly.com/question/2102943
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