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Verdich [7]
3 years ago
12

I need some help on my hw! Find the area

Mathematics
2 answers:
Alex17521 [72]3 years ago
7 0

Answer:

<h2>840 mm²</h2>

Step-by-step explanation:

Formula for area is A = lw, where a is area, l is length, and w is width.

A = lw

Insert correct values

A = 42(20)

A = 840

PLEASE MARK BRAINLIEST!

Andrej [43]3 years ago
3 0
Area is length times width 42x20=840
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What is the sum of all the integers between 19 and 77
victus00 [196]
Think of it this way: Lets add numbers in pairs, starting at the very outer 2 numbers (19 and 77)  then go in by one and add the second number and the second to last (20 and 76), then (21 and 75) and so on.  The sum of all of these pairs are all the same: 96.  How many 96s will we have?  Well since we're coming from each end toward the middle adding pairs we will have half the distance between 19 and 77, that is (77-19)/2 = 29.  So we can actually just take 96*29 = 2784.  This is the sum of all numbers between 19 and 77
7 0
3 years ago
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Henry is up for retirement after 35 long years at his pharmacy. Before retiring, he would like to know how much he would receive
satela [25.4K]

To find how much Henry can expect to receive from Social Security on a monthly basis, we first need to find how much he cant expect to receive from social security per year.

We know form our problem that Henry averaged an annual salary of $45,620, so to find how much can Henry expect to receive from Social Security per year, we just need to find the 42% of $45,620.

To find the 42% of $45,620, we are going to convert 42% to a decimal by dividing it by 100%, and then we are going to multiply the resulting decimal by $45,620:

\frac{42}{100} =0.42

Social security annual payment = (0.42)($45,620) = $19,160.40

Since there are 12 month in a year, we just need to divided the social security annual payment by 12 to find how much he can expect to receive each month.

Social security monthly payment = \frac{19,160.40}{12} = $1.596.70

We can conclude that Henry can expect to receive $1.596.70 monthly from Social Security.

3 0
3 years ago
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Write one sine and one cosine equation for each graph below.
pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x  

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.  

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x  

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

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a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

6 0
3 years ago
Explain how to graph the following including asymptotes and key features. f(x)=3^x+2
sattari [20]

Answer:

y=2

Step-by-step explanation:

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2 years ago
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