Answer:
x^2 -2x = 4x+1
2x^2 +12x = 0
9x^2 +6x -3=0
Step-by-step explanation:
A quadratic equation has the highest power of x being squared
x^2 -2x = 4x+1
2x^2 +12x = 0
9x^2 +6x -3=0
These are all quadratic equations
Use the equation and the map it might help so you can check your answer both ways tell me what the equation is and ill help a little more
Sin+cos=90
49+cos=90
cos=41
Number the tables as follows:
1 2
3 4
Eliminate 3 and 4 immediately, because for x = 2 the y values are wrong (3 and 1).
In tables 1 and 2, the input (1) produces the correct output (-1).
So we have to determine which table agrees 100% with the system of equations given.
Comparing tables 1 and 2, row by row, we see that their contents are the same EXCEPT for the first rows. So focus on determing which of those 2 rows displays values that satisfy both given equations.
First I looked at y=2x-5, and subst. -1 for x. I got -7, which is correct in table 1 but not in table 2 (where the value would be -13).
Thus, table 1 correct represents the solution of the system of equations.