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hoa [83]
3 years ago
13

Collin Buys a TV for £720 depreciate at a rate of 4% per year how much will it be worth in three years

Mathematics
1 answer:
belka [17]3 years ago
8 0

Answer:

The worth of the TV after 3 years is £809.90208

Step-by-step explanation:

The answer to given question can be found from the anual depreciation formula and solving for the Future Value (F. V.) of the machine

The given parameters of the TV are;

The amount at which Collin buys the TV, P = £720

The rate at which the TV depreciates at, R = 4%

The number of years the depreciation is applied, T = 3 years

The amount the TV is worth after three years, 'A', is given as follows;

A = P \cdot \left(1 + \dfrac{R}{100} \right )^T

By plugging in the known values, we have;

A = 720 \cdot \left(1 + \dfrac{4}{100} \right )^3 = 809.90208

The amount the TV is worth after three years, A = £809.90208

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9 rides

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Can Anybody Help me?
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Answer:

x=8, y=-1

Step-by-step explanation:

The figure is said to be a rectangle, which means opposite sides have to be equal in length. From this, we can write a system of equations:

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There are a number of ways to solve this but I'll go with elimination--that means you need to try to remove one variable first by manipulating the equations and solve for the other variable. Then you use the solution to solve for the variable you initially removed. That sounds confusing, but let me show you how to do it.

If you multiply the first equation by 3 and the second equation by 2, you'll have have:

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Now, we can add these two equations. The y will cancel out, so we can easily solve for x.

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Answer:

1. 80 yd

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3. yes

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1. As we were asked to stay 240 feet away, and we will be on a soccer field and it has marked distances in yards we just have to pass our feet to yards.

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3.  

if they are diagonally the distance will be greater than 80, since the yards are parallel, because only the distance would remain only if they are on the same height

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