(x1,y1) = (-2,7)
m = -5
(x,y) = (a,2)
Forming the equation,
(y-y1) = m(x-x1)
y - 7 = -5[x - (-2)]
y - 7 = -5x - 10
y + 5x = -3
Putting the values of (x,y) we get,
2 + 5a = -3
5a = -5
a = -1
As you can see, in the table of the first function, f(2) = 18, and in the table of the second function g(2) = 18. Then, for x = 2, f(x) = g(x). and x =2 is the solution of the equation.
Answer: x = 2.
Answer:
7x^2+5x
Step-by-step explanation:
Given
Polynomial 1: 9x^2+8x
Polynomial 2: 2x^2+3x
We have to find subtraction of both
So,
9x^2+8x - (2x^2+3x)
First of all the brackets will be eliminated by multilying the minus sign
9x^2+8x-2x^2-3x
The terms with same power of variable will be written together
9x^2-2x^2+8x-3x
=7x^2+5x ..
Answer:
25
Step-by-step explanation:
turn 68% into a decimal (or keep as a percentage, your choice) and divide
17 divided by 0.68 (68% as a decimal) = 25
<u>Answer:</u>

<u>Step-by-step explanation:</u>
Given dimensions of the box = 20cm × 6cm × 4cm .
Dimension of the cube = 2cm × 2cm × 2cm .
Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,


<h3>
<u>Hence</u><u> the</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>cubes</u><u> </u><u>that</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>fitted</u><u> </u><u>in</u><u> the</u><u> </u><u>box </u><u>is</u><u> </u><u>6</u><u>0</u><u> </u><u>.</u></h3>