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Alla [95]
3 years ago
13

Evren used 24 centimeters of tape to wrap 3 presents. How many presents would Evren be able to wrap with 112 cm of tape?

Mathematics
1 answer:
Paul [167]3 years ago
3 0

Answer:

14

Step-by-step explanation:

Since we're given the conversion 24 cm for every 3 presents wrapped, we can divide our total amount of tape by this conversion, assuming a constant proportion.

Evren has 112 cm of tape. We can write the following proportion:

\frac{112}{x}=\frac{24}{3}, where x is the number of presents he can wrap with 112 cm.

Cross-multiplying, we have:

24x=336,\\x=\frac{336}{24}=\boxed{14\text{ presents}}

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4 0
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Simplify<br> x^2(y^3)^4/xy^5=x^a•y^b
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Step-by-step explanation:

x^2(y^3)^4/x.y^5 = x^a.y^b

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3 years ago
William sold half of his comic books and then bought 14 more he now has 24 with how many did he have in the beginning
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What is 10 2/1 divided by 2 1/4
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Step-by-step explanation:

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The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control a
Dafna11 [192]

Answer:

Probability that at least 490 do not result in birth defects = 0.1076

Step-by-step explanation:

Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.

To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects

Proof -

Given that,

P(birth that result in a birth defect) = 1/33

P(birth that not result in a birth defect) = 1 - 1/33 = 32/33

Now,

Given that, n = 500

X = Number of birth that does not result in birth defects

Now,

P(X ≥ 490) = \sum\limits^{500}_{x=490} {^{500} C_{x} } (\frac{32}{33} )^{x} (\frac{1}{33} )^{500-x}

                 = {^{500} C_{490} } (\frac{32}{33} )^{490} (\frac{1}{33} )^{500-490}  + .......+ {^{500} C_{500} } (\frac{32}{33} )^{500} (\frac{1}{33} )^{500-500}

                = 0.04541 + ......+0.0000002079

                = 0.1076

⇒Probability that at least 490 do not result in birth defects = 0.1076

4 0
2 years ago
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