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3 years ago

I’m sure this is easy but I hateeee geometry. help ASAP plsssss

Mathematics

1 answer:

hram777 [196]3 years ago

8 0

Given points

(-4,3)
(2,5)

Distance:-

$\\ \sf\longmapsto \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\\ \sf\longmapsto \sqrt{(2+4)^2+(5-3)^2}$

$\\ \sf\longmapsto \sqrt{(6)^2+(2)^2}$

$\\ \sf\longmapsto \sqrt{36+4}$

$\\ \sf\longmapsto \sqrt{40}$

$\\ \sf\longmapsto 6.2$

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Points and their residual values are shown in the table. a 3-column table with 5 rows. the first column is labeled x with entrie

maksim [4K]

The residual value, which is the farthest from the line of best fit for the table which shows points and their residual values, is 0.7.

<h3>What is residual value?</h3>

The residual value is the estimated value which is calculated for the end of the lease terms for a fixed asset.

Points and their residual values are shown in the table. A 3-column table with 5 rows.

x 1, 2, 3, 4, 5.
y 2, 3.5, 5, 6.1, 8.
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The simple regression line can be represented as,

$\hat y=\alpha +\beta X+\hat e$

Here α is the constant, β is the slope and <em>e </em>is the residue.

The point which is farthest from the best fit of the line is 3.5. At y=3.5, the value of residue is 0.7.

Thus, the residual value, which is the farthest from the line of best fit for the table which shows points and their residual values, is 0.7.

Learn more about the residual value here;

brainly.com/question/1168961

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2 years ago

Assume that f is continuous on [-4,4] and differentiable on (-4,4). The table gives some values of f'(x) x: -4, -3, -2, -1, 0, 1

kondaur [170]

$f$ will be increasing on the intervals where $f'(x)>0$ and decreasing wherever $f'(x)$ . Local extrema occur when $f'(x)=0$ and the sign of $f'(x)$ changes to either side of that point.

$f'(x)$ is positive when $x$ is between -4 and some number between -2 and -1, and also 2 (exclusive) and 4, so you can estimate that $f(x)$ is increasing on the intervals [-4, -2] and (2, 4].

$f'(x)$ is negative when $x$ is between some number between -2 and -1, up to some number less than 2. So $f(x)$ is decreasing on the interval [-1, 1].

You then have two possible cases for extrema occurring. The sign of $f'(x)$ changes for some $x$ between -2 and -1, and again to either side of $x=2$ .

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3 years ago

A circle has a radius of 12 inches. Find the length of the arc intercepted by a central angle of 120 degrees to the nearest tent

OlgaM077 [116]

Answer:

25.12 inches

Step-by-step explanation:

We have given the radius of the circle =12 inches

The central angle intercepted by the arc =120°

We have to find the length of the arc

So length of the arc is given by $2\pi \times r\times \frac{central\ angle}{360}$

$=\frac{2\times \pi \times 12\times 120}{360}=25.12inches$

So the length of the arc will be 25.12 inch

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3 years ago

Given a=-3,b=4 and c=-5, evaluate a-b-c<br><br> A.-12<br> B.-6<br> C-2

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Answer:

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3 years ago

What is median of 3 7 5 2 4 2 53 6 9 7 7 3 5 2 7 3 2 2 7

ludmilkaskok [199]

Answer:

Step-by-step explanation:

To find the median number of

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Number them from least to greatest

2 2 2 2 3 3 3 4 5 5 6 7 7 7 7 7 9 53

Since this isn't an even numbered set, all we do is cancel each number out equally on both sides until only one number which should be in the middle is left. This gives you an answer of 5

Hope this helps!

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3 years ago

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