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topjm [15]
3 years ago
8

In similar triangles, corresponding angles are congruent.t or f

Mathematics
1 answer:
Bingel [31]3 years ago
3 0
Corresponding angles in both similar and congruent triangles are congruent.  In similar triangles, the sides are in proportion, whereas in congruent triangles, the sides are also congruent,
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o-na [289]

Looks like its A  whose first term would be 4.

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The Jayden family eats at a restaurant that is having a 15% discount promotion. Their meal
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Step-by-step explanation:

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Consider this exponential equation:
ioda

Step-by-step explanation:

F( <em>x</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>(</em><em>3</em><em>)</em><em> </em><em>^</em><em> </em><em>x</em>

<em>Y</em><em> </em><em>intercept</em><em> </em>

<em>Let</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>0</em>

<em>f</em><em>(</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>5</em><em>×</em><em> </em><em>3</em><em> </em><em>^</em><em> </em><em>0</em>

<em>f</em><em>(</em><em>0</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>×</em><em> </em><em>1</em>

<em>f</em><em>(</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>5</em>

<em>X</em><em> </em><em>intercept</em><em> </em>

<em>let</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>o</em>

<em>0</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>^</em><em>x</em>

<em>No</em><em> </em><em>x</em><em> </em><em>intercept</em><em>/</em><em> </em><em>zero</em>

<em>therefore</em><em> </em>

<em>Vertical</em><em> </em><em>intercept</em><em> </em><em>(</em><em>0</em><em>;</em><em> </em><em>5</em><em>)</em>

<em>Domain</em><em> </em><em>XER</em>

<em>▪︎</em><em>this</em><em> </em><em>refer</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>X</em>

4 0
3 years ago
Help me with this please.
Ira Lisetskai [31]

Answer:

JL = 78

Step-by-step explanation:

MN is a midsegment. Based on the midsegment theorem,

MN = ½(JL)

MN = 5x - 16

JL = 4x + 34

Plug in the value

5x - 16 = ½(4x + 34)

5x - 16 = ½*4x + ½*34

5x - 16 = 2x + 17

Collect like terms

5x - 2x = 16 + 17

3x = 33

Divide both sides by 3

x = 11

✔️JL = 4x + 34

Plug in the value of x

JL = 4(11) + 34

JL = 44 + 34

JL = 78

5 0
3 years ago
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