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2 years ago

5

5. A video game console at Games Galore

1 answer:

dmitriy555 [2]2 years ago

5 0

Answer:

$319.60

Step-by-step explanation:

Normal Game console cost : $399.50

Discount: %20 (0.20)

$399.50×0.20= $79.90

Total cost of discount $79.90

$399.50-$79.90= $319.60

New cost after Discount= $319.60

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pochemuha

Not completely sure how to answer your question but all 20 questions where worth 5 points each which she would have gotten a 100 if she got all right but she got 15 which her score would be 75. I think in a ratio of correct to incorrect would be 75:100 , I'm not sure completely.

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3 years ago

Solve for x (x+4)/3 = 2.<br><br>a. x = -2<br><br>b. x=2<br><br>c. x = 2/3<br><br>d. x= -10/3

Ronch [10]

Answer:

<h2>The answer is option B</h2>

Step-by-step explanation:

$\frac{x + 4}{3} = 2$

To solve it first of all cross multiply

That's

x + 4 = 6

Move 4 to the right side of the equation

The sign changes to negative

That's

x = 6 - 4

We have the final answer as

<h3>x = 2</h3>

Hope this helps you

8 0

3 years ago

What’s the formula that will help ted?

madam [21]

Answer:

t = 0.002n

Step-by-step explanation:

You are given what t and n should be. Each kilogram will yield $0.002

5 0

3 years ago

PLEASE DON'T IGNORE!

Debora [2.8K]

Answer is b hope this helps

8 0

3 years ago

Assume that a policyholder is four times more likely to file exactly two claims as to file exactly three claims. Assume also tha

kykrilka [37]

Answer:

1.3125

Step-by-step explanation:

Given that our random variable $X$ follows a Poisson distribution $P(X=k)=\frac{\lambda^k e^-^p}{k!} \ \ \ \ \ \ \ \ p=\lambda$

Evaluate the formula at $k=2,3:$

$P(X=2)=0.5\lambda^2e^{-\lambda}\\\\P(X=3)=\frac{1}{6}\lambda^2e^{-\lambda}$

#since

$4P(X=2)=P(X=3);\\\\0.5\lambda^2e^{-\lambda}=4\times\frac{1}{6}\lambda^3e^{-\lambda}\\\\0.5\lambda^2=\frac{2}{3}\lambda^3\\\\0.75=\lambda$

The mean and variance of the Poisson distributed random variable is equal to $\lambda$ :

$\mu=\lambda=0.75\\\sigma ^2=\lambda=0.75$

#By property variance:

$\sigma ^2=V(X)=E(X^2)-(E(X))^2=E(X^2)\\\\E(X^2)=\sigma^2+\mu^2=0.75+0.75^2=1.3125$

The expectation is 1.3125

4 0

3 years ago