Answer:
decreasing at 390 miles per hour
Step-by-step explanation:
Airplane A's distance in miles to the airport can be written as ...
a = 30 -250t . . . . . where t is in hours
Likewise, airplane B's distance to the airport can be written as ...
b = 40 -300t
The distance (d) between the airplanes can be found using the Pythagorean theorem:
d^2 = a^2 + b^2
Differentiating with respect to time, we have ...
2d·d' = 2a·a' +2b·b'
d' = (a·a' +b·b')/d
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To find a numerical value of this, we need to find the values of its variables at t=0.
a = 30 -250·0 = 30
a' = -250
b = 40 -300·0 = 40
b' = -300
d = √(a²+b²) = √(900+1600) = 50
Then ...
d' = (30(-250) +40(-300))/50 = -19500/50 = -390
The distance between the airplanes is decreasing at 390 miles per hour.
Answer:
x ≈ - 1.28
Step-by-step explanation:
Using the rule of logarithms
x = n ⇔ x = 
Given
ln(x + 4) = 1 , then
x + 4 = 
( subtract 4 from both sides )
x = - 4 = - 1.28 ( to the nearest hundredth )
Answer:
heyyyyyy
Step-by-step explanation:
Answer:
slope: -3/5
y-intercept (0,3)
x - y
0 3
5 0
Step-by-step explanation:
I just did it
