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slavikrds [6]
3 years ago
9

How to find angles on two Line intersect

Mathematics
1 answer:
Ivan3 years ago
7 0
Hello!

Vertical angles are always congruent

This means that 3x - 35 = 130

We can solve this algebraically

3x - 35 = 130

Add 35 to both sides

3x = 165

Divide both sides by 3

x = 55

The angle AOB and AOC are supplementary which means they add to 180

First we have to find what angle AOB equals

3(55) - 35 = 130

We can subtract 180 by this number to get angle AOC

180 - 130 = 50

Angle AOC is 50

The answers are x = 55 and AOC = 50

Hope this helps!
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What is the equation of a line that is perpendicular to −x+3y=9 and passes through the point (−3, 2) ?
vekshin1

The equation of line that is perpendicular to the line -x+3y =9  and passes through the point \left({-3,2}\right)  is \boxed{{\mathbf{y=-3x-7}}} .

Further explanation:

It is given that the equation of line is -x+3y =9  and passes through point \left({-3,2}\right) .

Rewrite the given equation -x+3y =9  as follows:

\begin{aligned}-x+3y&=9\\3y&=9+x\\y&=\frac{9}{3}+\frac{1}{3}x\\y&=\frac{1}{3}x+3\\\end{aligned}

Now, compare the obtained equation of line y=\frac{1}{3}x+3  with the standard equation of line y=mx+b .

\begin{aligned}m&=\frac{1}{3}\\b&=3\\\end{aligned}

Therefore, the slope is \frac{1}{3} .

It is given that both lines are perpendicular to each other so the product of slope must be equal to -1 .

{m_1}\cdot {m_2}=-1                                                          …… (1)

Substitute \frac{1}{3}  for {m_1}  in equation (1) to obtain the value of slope {m_2} .

\begin{aligned}\frac{1}{3}\cdot{m_2}&=-1\\{m_2}&=-3\\\end{aligned}

Therefore, the slope is -3 .

It is given that the line passes through point \left({-3,2}\right) .

The point-slope form of the equation of a line with slope m  passes through point \left({{x_1},{y_1}}\right) is represented as follows:

y-{y_1}=m\left({x-{x_1}}\right)                                      …… (2)

Substitute -3  for {x_1} , 2  for {y_1}  and -3  for m  in equation (2) to obtain the equation of line.

\begin{aligned}y-2&=-3\left({x-\left({-3}\right)}\right)\\y-2&=-3\left({x+3}\right)\\y&=-3x-9+2\\y&=-3x-7\\\end{aligned}

Therefore, the equation of line is y=-3x-7 .

Thus, the equation of line that is perpendicular to the line -x+3y=9  and passes through the point \left({-3,2}\right)  is \boxed{{\mathbf{y=-3x-7}}} .

Learn more:

1. Which classification best describes the following system of equations? <u>brainly.com/question/9045597 </u>

2. What is the value of x  in the equation x-y=30  when y=15 ? <u>brainly.com/question/3965451 </u>

3. What are the values of x? <u>brainly.com/question/2093003</u>

Answer Details:

Grade: Junior High School

Subject: Mathematics

Chapter: Coordinate Geometry

Keywords: Coordinate Geometry, linear equation, system of linear equations in two variables, variables, mathematics, equation of line, line, passes through point.

6 0
4 years ago
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Mrs. Lopez cut 46 cm of yarn miss Hamilton cut 22 cm less than Miss Lopez how many centimeters of yarn does Miss Hamilton cut
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Answer: 24 cm

Step-by-step explanation:

Mrs Lopez cut 46cm of yarn.

Miss Hamilton then cut 22cm less than what Mrs Lopez had cut.

Mrs. Hamilton must have therefore cut:

This is a case of subtraction:

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irina1246 [14]
14 = -(p-8)

Step 1 : Distribute the negative sign. This is equivalent to multiplying each term in the parenthesis by -1.
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Step 3: Multiply everything by -1 to get what p is equivalent to.
6 * -1 = -p * -1
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Which can be rewritten as
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(6x2)+(6x3) is correct
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