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3 years ago

Please help me with this question and please tell me how I would put this into a calculator please...

Mathematics

1 answer:

AnnyKZ [126]3 years ago

3 0

Answer:

Step-by-step explanation:

$\frac{2}{3}x+4=\frac{2}{3} *\frac{3}{1}+4 = 2+4=6$

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Please help me with my delta math

astra-53 [7]

Answer:

Use “ Math- way”

Step-by-step explanation:

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5 0

3 years ago

Simplify ((1/x)-(1/y))/((1/x)+(1/y))

In-s [12.5K]

<span>Simplify ((1/x)-(1/y))/((1/x)+(1/y))</span>

y-x
______

y+x

7 0

3 years ago

Select an equation for this graph please help me.

MrRissso [65]

A is the answer.

First, figure out all the coordinates for the points marked red( I Did this for all except first one, which was not on the right point)

They were:

-1,1

0,2

1,4

2,8

3,16.

Then, we must do trial and error for each of the options until we find one that fits perfectly. Luckily, the first option was right!

Hope this helps

3 0

3 years ago

If f(x) =-2+8 and g(x) = square root of x+9 which statement is true

lidiya [134]

The statement that -6 is in the domain of f(g(x)) is true

<h3>Complete question</h3>

If f(x) = -2x + 8 and g(x) = $\sqrt{x + 9$ , which statement is true?

-6 is in the domain of f(g(x))
-6 is not in the domain of f(g(x))

<h3>How to determine the true statement?</h3>

We have:

f(x) = -2x + 8

$g(x) = \sqrt{x + 9$

Start by calculating the function f(g(x)) using:

f(g(x)) = -2g(x) + 8

Substitute $g(x) = \sqrt{x + 9$

$f(g(x)) = -2\sqrt{x + 9} + 8$

Set the radicand to at least 0

$x + 9 \ge 0$

Subtract 9 from both sides

$x \ge -9$

This means that the domain of f(g(x)) are real numbers greater than or equal to -9. i.e. -9, -8, -7, -6, ...........

Hence, the statement that -6 is in the domain of f(g(x)) is true