(x+5)/4=1/2
first get rid of the fraction
multiply both sides by 4
x+5=2
subtract 5
x=-3
(2x+1)/(4x-1)=2/3
get rid of the fractions,
multiply both sdies by (4x-1)(3)
(2x+1)(3)=(2)(4x-1)
distribute
6x+3=8x-2
subtract 6x form both sdies
3=2x-2
add 2
5=2x
divide by 2
5/2=x
Y= x + 3
1. Find the gradient(slope)
1 - 7 / - 2 - 4
=1
2. Find the y. Intercept ( c )
Y = x + c
Replace by any of the two coordinates given (4 , 7 )
7 = 4 + c
C= 3
Equation => Y = x + 3
Well diameter will be the diagnol of that square..
let side of square be x, then diagonal will be root2 * x = diameter
so, raidus will be = dia/ 2
= (root2 * x ) /2
Answer:
$298
Step-by-step explanation:
Profit = Income - Cost
2 tires for 35 each, so total cost is 2*35=70. Sold for 65 each, so income is 2*65=130. Profit is 130 - 70 = $60.
3 rims for 75 each, so total cost is 3*75=225. Sold 136 each, so income is 3*136=408. Profit is 408 - 225 = $183.
5 headlight covers for 4 each, so total cost is 5*4=20. Sold for 15 each, so income is 5*15=75. Profit is 75 - 20 = $55.
Total profit = 60 + 183 + 55 = $298
Answer: A & C
<u>Step-by-step explanation:</u>
HL is Hypotenuse-Leg
A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
a leg from ΔABC ≡ a leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
B) a leg from ΔABC ≡ a leg from ΔFGH
the other leg from ΔABC ≡ the other leg from ΔFGH
Therefore LL (not HL) Congruency Theorem can be used.
C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
at least one leg from ΔABC ≡ at least one leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
D) an angle from ΔABC ≡ an angle from ΔFGH
the other angle from ΔABC ≡ the other angle from ΔFGH
AA cannot be used for congruence.
