Find the vertex of this parabola.

Mathematics

1 answer:

Rashid [163]2 years ago

4 0

Answer:

The vertex of this parabola is (1, 14).

Step-by-step explanation:

To find the vertex of this parabola, one approach is to determine the equation of the axis of symmetry: evaluate x = -b / (2a), where a, b and c are the coefficients of the x^2, x and x^0 terms respectively.

Here a = -2, b = 4 and c = 12.

Thus, the axis of symmetry is x = -4 / (2· -2), or x = 1.

The function value at x = 1 is y = -2(1)^2 + 4(1) + 12, or y = -2 + 4 + 12 = 14.

The vertex of this parabola is (1, 14).

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If point A is located at (-3,-1) and there are 10 points between A and B, what could be the possible coordinates for point B?

Nataly [62]

Answer:

Step-by-step explanation:

By drawing the point (-3,-1) in the coordinate plane we find the graph shown below. Since there are 10 points between points A and B, we need to start at point A and then we have to move 11 units either to the right, to the left, up, or down .

1. MOVING TO THE RIGHT:

From point A, move 11 units horizontally to the right to come to point B:

(-3+11, -1) = (8, -1)

2. MOVING TO THE LEFT:

From point A, move 11 units horizontally to the left to come to point B:

(-3-11, -1) = (-14, -1)

3. MOVING UPWARD:

From point A, move 11 units vertically upward to come to point B:

(-3, -1+11) = (-3, 10)

4. MOVING DOWNWARD:

From point A, move 11 units vertically downward to come to point B:

(-3, -1-11) = (-3, -12)

So this are the basic movements you can get to find point B. You also can move diagonally upwards or downwards in whose case you would find other four points. The graph below shows a red point which is A, and the other points are in black color and represent B.