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Fudgin [204]
3 years ago
5

Sheral got theses socres on her spelling test

Mathematics
2 answers:
mel-nik [20]3 years ago
6 0
Add them all together and then divide the sum by 5 and you get the answer
svlad2 [7]3 years ago
4 0
All you do is add up all test scores then divide by number of tests, so you get 450/5, and thats an average of 90%
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1. Solve the equation.<br>10+Z<br>2=<br>-3​
Xelga [282]

Answer:

Z=i\sqrt13} , -i \sqrt{13}

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Tell which is greater one inch or one centimeter?
11Alexandr11 [23.1K]

Answer:

An inch is greater than a centimeter.

Step-by-step explanation:

5 0
3 years ago
Problem
Aleksandr-060686 [28]

Answer:

-\dfrac{463}{7}

Explanation:

Given equation: 2x² - 6x - 7 = 0

In quadratic equation: ax² + bx + c

Sum \ of \ roots : \alpha  + \beta  = \dfrac{-b}{a}

product \ of \ roots : \alpha \beta  = \dfrac{c}{a}

So, here given:

Sum : \alpha  + \beta  = \dfrac{-(-6)}{2}  = 3

Product : \alpha \beta  = \dfrac{-7}{2}  = - 3.5

For finding value:

\dfrac{\alpha^3}{\beta }  + \dfrac{\beta^3 }{\alpha }

join fractions

\dfrac{\alpha^4+ \beta^4}{\alpha \beta }

factor out

\dfrac{(\alpha^2 + \beta ^2)^2 -2\alpha ^2 \beta  ^2  }{\alpha \beta }

when factored more

\dfrac{((\alpha + \beta)^2 -2\alpha \beta )^2 -2(\alpha \beta)^2 }{\alpha \beta }

insert values inside

\dfrac{((3)^2 -2(-3.5) )^2 -2(-3.5)^2 }{-3.5 }

calculate for value

-\dfrac{463}{7}

4 0
2 years ago
Find the equation in slope intercept form and standard form of the line that passes through (4,-3) and is perpendicular to 3x-y=
Tcecarenko [31]

The given line is y = 3x - 5 after adding Y and subtracting 5 from both sides.

The slope of this given line is 3.

Therefore, the slope of the perpendicular line is -1/3, as it must be the negative reciprocal.

The general form of a line equation in slope intercept form is y = Mx+B where M is the slope and B is the intercept.

Solving for B is: B = y- Mx

So the intercept of the perpendicular line with slope M=-1/3 and passing through (x=4, y=-3) is

y M * x

B = -3 - (-1/3)*4 =

-3 + 1/3*4 = <-- subtracting the negative is the same as adding the positive; definition of subtraction

-3 + 4/3 = <-- multiplies the fractions first per order of mixed operations

-9/3 + 4/3 <-- common denominator is 3

= -5/3

So the equation of the perpendicular line is y = -1/3X + -5/3 = -1/3X-5/3

Notice when X=4, y = -1/3(4) - 5/3 = -4/3 - 5/3 = -9/3 = -3 as expected

5 0
4 years ago
What is the domain of y equals -1/4x squared +1/2x minus 13/4?
makvit [3.9K]
If your equation is y=- \frac{1}{4}  x^{2} + \frac{1}{2} x- \frac{13}{4}, then the domain is all real numbers (-∞, ∞).

If your equation is y = - \frac{1}{4 x^{2} } + \frac{1}{2x} - \frac{13}{4},
then the domain is all real numbers except zero (-∞, 0)∪(0, ∞)
5 0
4 years ago
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