Answer:
Step-by-step explanation:
srry if its wrong but I think it's right :)
btw for the first one
p=19.53
Answer:
2/29 or 0.06896551724
Step-by-step explanation:
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 152.5
For the alternative hypothesis,
µ ≠ 152.5
This is a two tailed test.
Since no population standard deviation is given, the distribution is a student's t.
Since n = 231
Degrees of freedom, df = n - 1 = 231 - 1 = 230
t = (x - µ)/(s/√n)
Where
x = sample mean = 148.9
µ = population mean = 152.5
s = samples standard deviation = 27.4
t = (148.9 - 152.5)/(27.4/√231) = - 2
We would determine the p value using the t test calculator. It becomes
p = 0.047
Since alpha, 0.05 > thanthere sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals the p value, 0.047, then we would reject the null hypothesis. Therefore, At a 5% level of significance, there is sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals
5/11
11 goes into 5 zero times (0.)
11 goes into 50 four times with a remainder of 6 (0.4)
11 goes into 60 five times with a remainder of 5 (0.45)
11 goes into 50 four times with a remainder of 6 (0.454)
11 goes into 60 five times with a remainder of 5 (0.4545)
The answer is .45 with a bar on top of both the 4 and the 5.
