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aev [14]
3 years ago
5

A bakery uses 63.9 kilograms of flour each hour. How many kilograms of flour will the bakery use in 18 hours?

Mathematics
1 answer:
bagirrra123 [75]3 years ago
7 0
Hello!

To solve this you multiply how many kilograms of flour used an hour by the amount of hours

63.9 * 18 = 1150.2

The answer is 1150.2 kilograms of flour is used in 18 hours

Hope this helps!
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Three items weighing 5.28 kg 3.68 kg and 5.49 kg are to be posted but are found to be overweight. By how much does the total wei
NikAS [45]

Answer:

1.69 kg

Step-by-step explanation:

add than subtract

yep thats it

3 0
3 years ago
Will give brainiest Find the equation of the straight line parallel to the y-axis and passes through the point (-2, 3). _____
IrinaVladis [17]

Answer:

Step-by-step explanation:

8 0
2 years ago
A- CE=CD <br> B- CE = CA <br> C- BF=DF <br> D- DF=EF<br><br> please help!!
Oksana_A [137]

The perpendicular bisector theorem gives the statements that ensures

that \overleftrightarrow{FG} and \overleftrightarrow{AB} are perpendicular.

The two statements if true that guarantee  \overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB} are;

  • \overline{CE} = \overline{CD}
  • \overline{DF} = \overline{EF}

Reasons:

The given diagram is the construction of the line \mathbf{\overleftrightarrow{FG}} perpendicular to line \mathbf{\overleftrightarrow{AB}}.

Required:

The two statements that guarantee that  \overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB}.

Solution:

From the point <em>C</em> arcs <em>E</em> and <em>D</em> are drawn to cross line \overleftrightarrow{AB}, therefore;

\overline{CE} = \mathbf{\overline{CD}} arcs drawn from the same radius.

\overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB}, given.

Therefore;

\overline{DF} = \overline{EF}  by perpendicular bisector theorem.

Learn more about the perpendicular bisector theorem here:

brainly.com/question/11357763

7 0
3 years ago
What would be the actual length, if the length of the model is 25 ft and the scale factor is less
Sidana [21]

Answer:

20ft

Explanation:

You multiply the model length by the scale factor to find the actual length. <u>If the scale factor is less than zero, then the actual size will be smaller than the model</u>. Therefore, your answer would be 20ft.

Specifically, the scale factor is .8 if the actual size is 20ft, 1 if the actual size is 25ft, and 1.2 if the actual size is 30ft.

6 0
4 years ago
The area of the base of the oblique pentagonal pyramid is 50 cm^2 and the distance from the apex to the center of the pentagon i
Verdich [7]
The complete question in the attached figure

Part a) 
we know that
ABC is a right triangle
∠ACB=45°
AC=hypotenuse------> 6√2 cm
sin 45=AB/AC-----> AB=AC*sin 45----> AB=6√2*√2/2----> AB=6 cm

the answer part a) is
AB=6 cm

Part b) 
we know that
volume of the pyramid=(1/3)*Area of the base*height
area of the base=50 cm²
height=6 cm
so
volume of the pyramid=(1/3)*50*6----> 100 cm³

the answer part b) is 
100 cm³

5 0
3 years ago
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