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3 years ago

Please help me on this!

Mathematics

1 answer:

yanalaym [24]3 years ago

6 0

Answer:

${9}^{ - 8}$

Step-by-step explanation:

$\frac{ {9}^{ - 5} }{ {9}^{3} }$

${9}^{ - 5 - (3)}$

${9}^{ - 5 + (- 3)}$

${9}^{ - 8}$

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2 years ago

The fitness center held a weight loss competition in which 128 people participated. The amount of weight loss was normally distr

iris [78.8K]

Answer:

Step-by-step explanation:

Given :

Sample size, n = 128

Mean, μ = 18

Standard deviation, σ = 5.4

Number of people who lost atleast 15 pounds :

The Zscore = (x - μ) / (σ)

Zscore = (15 - 18) / 5.4

Zscore = - 3 / 5.4

Zscore = - 0.5555

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2 years ago

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sergij07 [2.7K]

Answer:

3x - y + $\frac{- 5x^2y}{3x^3 + 2x^2y - xy^2}$

Step-by-step explanation:

Hooboy okay here we go.

1.) Rewrite the equation in the classic division method

3x³ + 2x²y - xy² $\sqrt{9x^4 + 3x^3y - 5x^2y^2 + xy^3}$

2.) Divide using normal division rules, but it's super hard now 'cause there are letters involved. Basically, what can you multiply 3x³ by to get 9x⁴? 3x. So 3x is your first number. Then multiply everything else by 3x, and subtract

3x³ + 2x²y - xy² $\sqrt{9x^4 + 3x^3y - 5x^2y^2 + xy^3}$

-(9x⁴ + 6x³y - 3x²y²)

= 0 - 3x³y - 2x²y² - 5x²y + xy³

Now lets do that again, see what happens. 3x³ times -y should get -3x³y

3x - y

3x³ + 2x²y - xy² $\sqrt{9x^4 + 3x^3y - 5x^2y^2 + xy^3}$

- (9x⁴ + 6x³y - 3x²y²)

= 0 - 3x³y - 2x²y² - 5x²y + xy³

- ( - 3x³y - 2x²y² + xy³)

= 0 + 0 - 5x²y + 0

So! From this information, we can know that the answer is 3x-y with a remainder of - 5x²y. How it's written is shown above, in "Answer"

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2 years ago