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stich3 [128]
3 years ago
14

What is the reference angle for 11pi/6? Explain your thinking.

Mathematics
1 answer:
il63 [147K]3 years ago
8 0

First we need to see in which quadrant 11pi/6 lies And it lies in fourth quadrant. And to find the reference angle in the fourth quadrant, we need to subtract the given angle from 2 pi . For e.g if the angle is 5pi/3, then the reference angle is 2pi - (5pi/3) = pi/3 .

So for the given question, reference angle of 11pi/6 is

2 \pi - \frac{11 \pi}{6} = \frac{ \pi}{6}

And that's the required reference angle .

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Zane performs the elementary row operation represented by R2-½R1 on matrix A.​
UkoKoshka [18]

Answer:

[2 5 0]

[-7 -11/2 12]

Step-by-step explanation:

We want to perform elementary row operation represented by R2 - ½R1 on matrix A in the figure attached.

Now, matrix A is given as;

[2 5 0]

[-6 -3 12]

Now, R1 is row 1 = [2 5 0]

R2 is row 2 = [-6 -3 12]

Thus, R2 - ½R1 = [-6 -3 12] - ½[2 5 0]

This gives;

[-6 -3 12] - [1 5/2 0] = [-7 -11/2 12]

Now,[-7 -11/2 12] will be the new row 2 since it's just an elementary row operation we did on the Matrix A.

Thus, the new matrix is now;

[2 5 0]

[-7 -11/2 12]

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1) Area = leg(1) * leg(2) * .5 = 15 * 36 * .5 = 270

Perimeter = leg(1) + leg(2) + hypotenuse = 15 + 36 + 39 = 90

2) Area = leg(1) * leg(2) = 20 * 80 = 1600

3) Median (divides it in 1/2)

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5) Altitude (makes 90 degree angle w/ base)

6)sqrt(30^2 + 16^2) = sqrt( 900 + 256) = sqrt(1156) = 34

7) sqrt(24^2 + 18^2) = sqrt( 576 + 324) = sqrt(900) = 30

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9) sqrt(150^2 - 90^2) = sqrt(22500 - 8100) = sqrt(14400) = 120

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